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lawyer [7]
3 years ago
11

When electrons are lost, a blank ion is formed​

Physics
1 answer:
Serhud [2]3 years ago
3 0

Answer:

Positive ions, or cations.

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What is the electrical consumption in KVA of a motor powered by a 3-phase, 60 Hz, 460 VAC supply that continuously draws 17 A
MrRa [10]

Answer:

15.34 kVA

Explanation:

A motor is a device that converts electrical energy into mechanical energy. It takes in electrical energy at the input and produce torque (motion) at the output.

The power consumption for a three phase motor is the product of voltage and current and √3. The √3 is because it is a three phase supply.

Hence Power (P) =√3 × voltage (V) × current (I)

P = √3 × V × I

Given that voltage (V) = 460 V, current (I) = 17 A. Hence:

P = √3 × V × I = √3 × 460 × 17 = 13544.64 VA

But 1000 VA = 1 kVA. Hence:

P=13544.64\ VA*\frac{1\ kVA}{1000\ VA}=13.54\ kVA

8 0
3 years ago
Describe the path of an electrical impulse as it moves through a neuron. You must use the words axon
Nat2105 [25]

Answer:

The nerve impulse is not transmitted with the same speed in all neurons. It depends on whether or not the axon is surrounded by cells, the Schwann cells, which produces a white substance, the myelin sheath, which prevents the passage of the nerve impulse and causes you to "jump" between the spaces without the sheath of Myelin (Ranvier nodules), so the speed will be higher.

This type of nerve impulse spread is called "saltatory conduction or spread."

Explanation:

Neurons are cells that have the ability to transmit the nerve impulse in the form of an electric current. The nerve impulse only spreads in one direction. When a neuron is stimulated, electrical changes originate that begin in the dendrites, pass through the neuronal body, and end in the axon.

Neurons can also be classified according to whether or not they have myelin:

- Myelinic neurons Its axons are thicker and the nerve impulse spreads more quickly thanks to the saltatory conduction.

- Unmyelinated neurons They grow myelin, so they drive the nerve impulse more slowly.

The nerve impulse is transmitted along a neuron through a depolarization process:

- Initially, the membrane is polarized. On the outside of the membrane, ions with positive charge abound and on the inside, those with negative charge. This is maintained by the action of the sodium-potassium pump and is called the resting potential.

- When a stimulus arrives, the permeability increases for the sodium ions, which enter the cell, so that the polarity is reversed at that point, leaving more positive charge inside in that area. This alteration is called action potential.

- This depolarization leads to the redistribution of the ions, the nearby sodium channels open, and the adjacent area is also depolarized, and this, in turn, to that of the area that follows, as if they were the dominoes . In this way the nerve impulse travels like a wave along the axon.

- Once the nerve impulse has traveled the entire axon, in thousandths of a second, repolarization or restoration of the ion concentrations characteristic of the resting state occurs.

3 0
3 years ago
J-s. If your 1400-kg car is parked in an 8.54-m-long garage, what is the uncertainty in its velocity? cm/s the tolerance is +/-2
IgorC [24]

Answer:

\Delta v = 4.41 \times 10^{-37} cm/s

Explanation:

As per Heisenberg's uncertainty principle we know that

\Delta P \times \Delta x = \frac{h}{4\pi}

so here we have

\Delta P = m\Delta v

\Delta x = 8.54 m

now from above equation we have

m\Delta v \times (8.54) = \frac{h}{4\pi}

1400(\Delta v) \times (8.54) = \frac{6.626 \times 10^{-34}}{4\pi}

\Delta v = 4.41 \times 10^{-39} m/s

\Delta v = 4.41 \times 10^{-37} cm/s

8 0
3 years ago
4. An object is thrown vertically upward with a speed of 25 m/s. How much time passes before it
vlada-n [284]

Answer:

<em>Option b is correct: 4.1 s</em>

Explanation:

<u>Vertical Launch</u>

An object launched thrown vertically upward where air resistance is negligible, reaches its maximum height in a time t, given by the equation:

\displaystyle t=\frac{v_o}{g}\qquad\qquad[1]

Where vo is the initial speed and g is the acceleration of gravity g=9.8 m/s^2.

Once the object reaches that point, it starts a free-fall motion, whose speed is (downward) given by:

v_f=g.t\qquad\qquad[2]

The object considered in the question is thrown with vo=25 m/s. The time taken to reach the maximum height is given by [1]:

\displaystyle t=\frac{25}{9.8}=2.551\ sec

The object starts its falling motion and at some time, it has a speed of vf=15 m/s. Let's find the time by solving [2] for t:

\displaystyle t=\frac{15}{9.8}=1.531\ sec

The total time taken by the object to go up and down is

t_t=2.551\ s+1.531\ s=4.081\ s

a. This option is incorrect because it's far away from the answer.

d. This option is incorrect because it's far away from the answer.

b. This option is correct because it's a good approximation to the calculated answer.

e. This option is incorrect because it's far away from the answer.

c. This option is incorrect because it's far away from the answer.

5 0
3 years ago
RESUME EXAMPLE??<br>Comment what a resume must look like done
CaHeK987 [17]

Answer:

Explanation:

I don't understand your question

8 0
3 years ago
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