Answer:
T = 5163.89 N
Explanation:
Newton's first law:
∑F =0 Formula (1)
∑F : algebraic sum of the forces in Newton (N)
We define the x-axis in the direction parallel to the movement of the car on the ramp and the y-axis in the direction perpendicular to it.
Forces acting on the car
W: Weight of the car : In vertical direction
FN : Normal force : perpendicular to the ramp
T :Tension force: at angle of 31.0° above the surface of the ramp
Calculated of the Weight of the car (W)
W = m*g m: mass g:acceleration due to gravity
W = 1130-kg* 9.8 m/s² = 11074 N
x-y weight components
Wx = 11074 N*sin 25.0° = 4680.07 N
Wy = 11074 N*cos 25.0° = 10036.45 N
x-y Tension components
Tx = T*cos 25.0°
Ty = T*sin 25.0°
Newton's first law:
∑Fx =0 Formula (1)
Tx-Wx = 0
T*cos 25.0° - 4680.07 = 0
T*cos 25.0° = 4680.07
T = 4680.07 / cos 25.0°
T = 5163.89 N
Force = mass x acceleration
Mass is given to be 250kg
Acceleration is given to be 5m/s^2
Force = 250kg x 5m/s^2 = 1,250 kgm/s^2 = 1,250 Newtons
Answer:
Sonia's grandfather was not able to see clearly after returning from his walk on a bright sunny day. He was about to hit a chair when Sonia held him and guided him to the nearby sofa, in sunny environment grandfather's eye is set according to high brightness, his pupils become small to lower the number of light rays entering his eye, when he returned from sunny environment to his house which was having low brightness so the pupils should enlarge to absorb more light to see clearly but due to old age his Ciliary muscle of the eye would have worn out and due to this poor coordination the image was not clear.
Work = force × distance
= 35 N × 200 m
= 7000 J
A) We balance the masses: 4(1.00728) vs 4.0015 + 2(0.00055)4.02912 vs. 4.0026This shows a "reduced mass" of 4.02912 - 4.0026 = 0.02652 amu. This is also equivalent to 0.02652/6.02E23 = 4.41E-26 g = 4.41E-29 kg.
b) Using E = mc^2, where c is the speed of light, multiplying 4.41E-29 kg by (3E8 m/s)^2 gives 3.96E-12 J of energy.
c) Since in the original equation, there is only 1 helium atom, we multiply the energy result in b) by 9.21E19 to get 3.65E8 J of energy, or 365 MJ of energy.
