Answer:
So, the energy of two hydrogen atoms is lower when the two atoms are together than when the two atoms are apart; that is why they stay together.
Explanation:
Answer:
The final mass of sample is 1.3 g.
Explanation:
Given data:
Half life of H-3 = 12.32 years
Amount left for 15.0 years = 3.02 g
Final amount = ?
Solution:
First all we will calculate the decay constant.
t₁/₂ = ln² /k
t₁/₂ =12.32 years
12.32 y = ln² /k
k = ln²/12.32 y
k = 0.05626 y⁻¹
Now we will find the original amount:
ln (A°/A) = Kt
ln (3.02 g/ A) = 0.05626 y⁻¹ × 15.0 y
ln (3.02 g/ A) = 0.8439
3.02 g/ A = e⁰°⁸⁴³⁹
3.02 g/ A = 2.33
A = 3.02 g/ 2.33
A = 1.3 g
The final mass of sample is 1.3 g.
Answer:
O₈¹⁷
Explanation:
An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.
All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other.
In given statement there are 8 electrons it means the atomic number of given atom is 8 so it would oxygen. The atomic mass of oxygen is 16 while in given statement mass is 17 it means it is the isotope of oxygen that have one more neutron than oxygen 16.
Isotope of an element have same atomic number but different atomic mass due to different number of neutrons.
In order to calculate the experimental percent error, we follow these steps:
1- Subtract one value from the other (order does not matter as we take absolute)
2- Divide the obtained number by the accepted or true value.
3- Multiply the fraction you got from step 2 by 100 to get the percentage of error.
Now, we will apply these steps on our problem:
1- Subtract one value from the other:
9.95 - 7.13 = 2.82
2- Divide by accepted value:
2.82 / 7.13 = 0.3955
3- Multiply by 100 to get the error percentage:
error percentage = 0.3955 x 100 = 39.55%
Answer:
27.98g/mol
Explanation:
Using ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
T = temperature (K)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
According to the information given:
V = 2.5L
P = 1.4 atm
T = 282K
n = ?
Using PV = nRT
n = PV/RT
n = 1.4 × 2.5/0.0821 × 282
n = 3.5/23.1522
n = 0.151mol
Using the formula to calculate molar mass of the elemental gas:
mole = mass/molar mass
Molar mass = mass/mole
Molar mass = 4.23g ÷ 0.151mol
Molar mass = 27.98g/mol
