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Mashcka [7]
2 years ago
8

ASAP please

Chemistry
1 answer:
choli [55]2 years ago
5 0
D.
0.220/0.2= 1.10 M
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When 0.250 moles of KCl are added to 200.0 g of water in a constant pressure calorimeter a temperature change is observed. Given
777dan777 [17]

Explanation:

Upon dissolution of KCl heat is generated and temperature of the solution raises.

Therefore, heat generated by dissolving 0.25 moles of KCl will be as follows.

             17.24 kJ/mol \times 0.25 mol

                = 4.31 kJ

or,             = 4310 J      (as 1 kJ = 1000 J)

Mass of solution will be the sum of mass of water and mass of KCl.

       Mass of Solution = mass of water + (no. of moles of KCl × molar mass)

                                    = 200 g + (0.25 mol \times 54.5 g/mol)

                                    = 200 g + 13.625 g

                                    = 213.625 g

Relation between heat, mass and change in temperature is as follows.

                             Q = mC \Delta T

where,    C = specific heat of water = 4.184 J/g^{o}C

Therefore, putting the given values into the above formula as follows.

                     Q = mC \Delta T

            4310 J = 213.625 g \times 4.184 J/g^{o}C \times \Delta T      

              \Delta T = 4.82^{o}C

Thus, we can conclude that rise in temperature will be 4.82^{o}C.

6 0
3 years ago
If 11.9 kJ are used to heat a sample of water the temperature increases from 20.0°C to
Kipish [7]

Answer:

m=4.51g

Explanation:

Hello!

In this case, since the energy involved during a heating process is shown below:

Q=mCp\Delta T

Whereas the specific heat of water is 4.184 J/(g°C), we can compute the heated mass of water by the addition of 11.9 kJ (11900 J) of heat as shown below:

m=\frac{Q}{Cp\Delta T}

Thus, by plugging in, we obtain:

m=\frac{11900J}{4.184\frac{J}{g\°C}(650\°C-20.0\°C)}\\\\m=4.51g

Best regards!

7 0
2 years ago
A particular exosolar system has five planets in total: A, B, C, D, and E. The table lists the orbital periods of these planets
sveta [45]

Answer:

The answer is in the picture below

Explanation:

8 0
2 years ago
Drag the tiles to the correct locations on the equation. Not all tiles will be used.
mel-nik [20]

Answer:

Tile 52 and three are incorrect

Explanation:

6 0
1 year ago
The usual units of density are : <br> cm3/ g<br> cm2/g<br> g/cm<br> Nm
Ad libitum [116K]
The usual units of density are g/cm.

You may have also seen g/mL used for density. Keep in mind that 1 cm = 1 mL.
3 0
3 years ago
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