ASAP please

The two rate statements below are not the same. Use the concept of unit rates to explain

olganol [36]

It’s definitely B but I’m not sure

8 0

3 years ago

A sample of 0.800 mol of nitrogen has a pressure of 0.600 atm and a

schepotkina [342]

Answer:

274K

Explanation:

5 0

3 years ago

Determine the number of moles of C5H12 that are contained in 357.4 g of the compound.

AlladinOne [14]

Answer: 4.96 moles

Explanation:

C5H12 is the chemical formula for pentane, the fifth member of the alkane family.

Given that,

number of moles of C5H12 = ?

Mass in grams = 357.4 g

Molar mass of C5H12 = ?

To get the molar mass of C5H12, use the atomic mass of carbon = 12g; and Hydrogen = 1g

i.e C5H12 = (12 x 5) + (1 x 12)

= 60g + 12g

= 72g/mol

Now, apply the formula

Number of moles = Mass / molar mass

Number of moles = 357.4g / 72g/mol

= 4.96 moles

Thus, 4.96 moles of C5H12 that are contained in 357.4 g of the compound.

4 0

3 years ago

One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su

Tpy6a [65]

Answer : The percent purity of $Fe_2O_3$ in the original sample is 87.94 %

Explanation :

The given balanced chemical reaction is:

$Fe_2O3+3CO\rightarrow 2Fe+3CO_2$

First we have to calculate the mass of Fe.

$\text{Moles of }Fe=\frac{\text{Mass of }Fe}{\text{Molar mass of }Fe}$

Molar mass of Fe = 55.8 g/mole

$\text{Moles of }Fe=\frac{1.79\times 10^3kg}{55.8g/mole}=\frac{1.79\times 10^3\times 1000g}{55.8g/mole}=3.15\times 10^4mole$

Now we have to calculate the moles of $Fe_2O_3$

From the balanced chemical reaction we conclude that,

As, 2 moles of Fe produced from 1 mole of $Fe_2O_3$

So, $3.15\times 10^4mole$ of Fe produced from $\frac{3.15\times 10^4}{2}=15750$ mole of $Fe_2O_3$

Now we have to calculate the mass of $Fe_2O_3$

$\text{ Mass of }Fe_2O_3=\text{ Moles of }Fe_2O_3\times \text{ Molar mass of }Fe_2O_3$

Molar mass of $Fe_2O_3$ = 159.69 g/mole

$\text{ Mass of }Fe_2O_3=(15750moles)\times (159.69g/mole)=2.515\times 10^6g=2.515\times 10^3kg$

Now we have to calculate the percent purity of $Fe_2O_3$ in the original sample.

Mass of original sample = $2.86\times 10^3kg$

$\text{Percent purity}=\frac{\text{Mass of }Fe_2O_3}{\text{Mass of sample}}\times 100$

$\text{Percent purity}=\frac{2.515\times 10^3kg}{2.86\times 10^3kg}\times 100=87.94\%$

Therefore, the percent purity of $Fe_2O_3$ in the original sample is 87.94 %

3 0

3 years ago

In the periodic table hydrogen is placed in Group 1A (group 1) and helium is placed in Group 8A (group 18). The most likely reas

Alexus [3.1K]

Answer:

This question appears incomplete

Explanation:

This question appears incomplete because of the absence of options. However, hydrogen is placed in group 1 because it has just one electron in it's outermost shell (which happens to be the only shell it has) just like every other group 1A/group 1 element. While helium is placed in group 8A/group 18 because it has a completely filled outermost shell (which is also the only shell it has) just like every other element in group 8A/group 18.

8 0

3 years ago