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elena-s [515]
3 years ago
7

3500kg of water are poured into a water tank and fill a volume equal to 3.5m^3. a. What is the density of the water?

Physics
1 answer:
Vaselesa [24]3 years ago
8 0

Answer:

a )

Density = mass / volume

= 3500 / 3.5

= 1000 kg m⁻³

b) gauge pressure = h d g

h is height of water column

d is density

g is acceleration due to gravity

Put the values in the equation above

Gauge pressure = .15 x 1000 x 9.8

= 1470 Nm⁻²

Atmospheric pressure = 100000 Nm⁻²

Total pressure

= 101470 N m⁻²

c ) Volume of water displaced = volume of object

= 55 x 10⁻⁶ m³

Buoyant Force = weight of displaced water

= 55 x 10⁻⁶ x 1000 x 9.8

= .539 N.

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Two identical loudspeakers 2.30 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi
Dimas [21]

Answer:

Abby is standing (4.5^2 + 2.3^2)^1/2   from the far speaker

D2 = 5.05 m from the far speaker

The difference in distances from the speakers is

5.05 - 4.5 = .55 m     (Let y be wavelength, lambda)

n y = 4.5

(n + 1) y = 5.05 for the speakers to be in phase at smallest wavelength

y = .55 m          subtracting equations

f = v / y = 340 / .55 = 618 / sec     should be the smallest frequency

8 0
3 years ago
At a certain elevation, the pilot of a balloon has a mass of 120 lb and a weight of 119 lbf. What is the local acceleration of g
Strike441 [17]

Answer:

31.905 ft/s²

Explanation:

Given that

Mass of the pilot, m = 120 lb

Weight of the pilot, w = 119 lbf

Acceleration due to gravity, g = 32.05 ft/s²

Local acceleration of gravity of found by using the relation

Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)

119 = 120 * a/32. 174

119 * 32.174 = 120a

a = 3828.706 / 120

a = 31.905 ft/s²

Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²

3 0
3 years ago
What is the wavelength of a wave with a frequency of 200Hz while traveling at 125.5m/s
nikdorinn [45]

Answer:

0.6275 metres

Explanation:

v = fl

125.5 = 200 * wavelength

125.5 / 200 = wavelength = 0.6275m

4 0
3 years ago
Answer all of these questions and you will get the brainlist
Rina8888 [55]
7) PE= Fwh = (72 m) (966 N) = 69552 Joules 7
8) zero PE=mass*g*height
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6 0
2 years ago
A small airplane takes on 302 l of fuel. If the density of the fuel is 0.821 g/ml, what mass of fuel has the airplane taken on?
ella [17]

To calculate the mass of the fuel, we use the formula

m = V \times  \rho

Here, m is the mass of fuel, V is the volume of the fuel and its value is V =302 \ L =  302 \ L \times \frac{10^{3}m L }{L} = 302 \times 10^{3} \ mL and  \rho is the density and its value of  0.821 g/mL.

Substituting these values in above relation, we get  

m = 302 \times 10^{3} \ mL \times 0.821 g/mL = 247942 g \\\\ m = 247. 94 \ kg

Thus, the mass of the fuel 247 .94 kg.

8 0
3 years ago
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