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Igoryamba
3 years ago
14

Select the classification for the following reaction. 2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g) a. precipitation b. acid-base c. redo

x d. combination e. none of the above
Chemistry
1 answer:
Alexeev081 [22]3 years ago
8 0

Answer:

The answer to your question: I think is letter c

Explanation:

                       2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)

a.- Precipitation: is incorrect because for this kind of reactions one of the products  must be a precipitate and in the reaction we see that NAOH is soluble in water (aq) and H2 is a gas, none of them precipitate.

b. acid - base: the reactants must be an acid and a base, and the reactants of this reaction has a base but it's in the products.

c. Redox: This reaction is a redox reaction because for this reaction the oxidation numbers of the reactants must change and this happen in this reaction (H changes from +1 to 0) and Na changes from 0 to +1.

d. Combination. In this reaction the reactants combine to form a new compound and this doesn't happen here.

e. None of the above. is false because letter C is correct.

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3 years ago
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formic acid, hcooh, is a weak acid with a ka equal to 1.8×10–4. what is the ph of a 0.0115 m aqueous formic acid solution?
kvasek [131]

The pH of a 0.0115 m aqueous formic acid solution is  mathematically given as

pH=2.8424

This is further explained below.

<h3>What is the ph of a 0.0115 m aqueous formic acid solution?</h3>

Generally,   the equation for the chemical equation is  mathematically given as

HCOOH   H^+ + HCOO

\quad C-C \alpha \quad C \alpha

&k a=\frac{c^2 \alpha^2}{e(1-\alpha)}\\\\&K_a=\frac{c \alpha^2}{1-\alpha_4} \quad|\gg\rangle \alpha\\\\&K_a=c \alpha^2\\\\&\alpha=\sqrt{\frac{k a}{c}}\\\\&\alpha=\sqrt{\frac{1.8 \times 10^{-4}}{0.0115}}\\\\&\alpha=\sqrt{156: 527710^{-4}}\\\\&\alpha=\sqrt{1.565 \times 1 \sigma^2}\\\\&\alpha=1.25 \times 10^{-1}\\\\&\alpha=0.125\\

&\left[\mathrm{H}^{+}\right]=\mathrm{C \alpha}\\\\&=0.125 \times 0.0115\\\\&=1.4375 \times 10^{-9}\\\\&P=-\log \left[H^{+}\right]\\\\&=-\log \left[1.4375 \times 10^{-3}\right]\\\\&P H=2.8424

Read more about  chemical equation

brainly.com/question/28294176

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8 0
1 year ago
15.0 g of cream at 16.4 °C are added to an insulated cup containing 100.0 g of coffee at 86.5 °C. Calculate the equilibrium temp
Marta_Voda [28]
115 grams total

15/115= 13%

109/115= 87%

.13x 16.4= .277

.87x 86.5= 75.255

75.255+.277= 75.532 deg C
or 75.5 as 3 significant digits
7 0
3 years ago
One of the substance acted upon by a catalytic converter in an automobile is carbon dioxide. State true or false
elena-14-01-66 [18.8K]
This is false because catalytic converters in an automobile don't act upon carbon dioxide. They burn carbon monoxide and other carbon gasses to create carbon monoxide and water.
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Round off or add zeros to the following calculated answers to give a final answer with three significant figures
sesenic [268]
In this case, 58.703 has five significant figures because the 3 at the end is significant and therefore makes the 0 significant as well. Since there are 5 significant figures, we need to round off the 7 to get 58.7, which has three significant figures.

Hope this helps.
8 0
3 years ago
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