Step-by-step explanation:
Given
Length (L) = 4 ft
Breadth (b) = 6 ft
height (h) = 3 ft
Volume (V)
= L * b * h
= 4 * 6 * 3
= 72 ft³
I think you could do is 9 squared + 12 squared = x squared
the 81+144=225
and the square root of 225 is 15
lets just say the answer you are looking for is 15
The measure of angle 8 is 88 degrees
Hello!
The equation to find the volume of a sphere you use the equation
r is radius which is half the diameter
put in 3.14 for pi and 12 for r
This gives us the answer of 7234.56 cubic units
Hope this helps!
Let's make clear the question:
"<span>During August, Boxer Company sells $364,000 in merchandise that has a one year warranty. Experience shows that warranty expenses average about 5% of the selling price. The warranty liability account has a credit balance of $12,000 before adjustment. Customers returned merchandise for warranty repairs during the month that used $8,600 in parts for repairs. The entry to record the estimated warranty expense for the month is:
a) Debit Estimated Warranty Liability $18,200; credit Warranty Expense $18,200.
b) Debit Warranty Expense $6,200; credit Estimated Warranty Liability $6,200. c) Debit Warranty Expense $18,200; credit Estimated Warranty Liability $18,200.
d) Debit Warranty Expense $14,800; credit Estimated Warranty Liability $14,800.
e) Debit Estimated Warranty Liability $8,600; credit Warranty Expense $8,600." </span>
First, calculate the average warranty expenses:
364000 × 5 ÷ 100 = 18200$
This amount has to be recorded both as a debit (debit warranty expenses) and as a credit (credit estimated warranty liability).<span>
Therefore, the correct answer is:
</span><span>c) Debit Warranty Expense $18,200; credit Estimated Warranty Liability $18,200.</span>