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gladu [14]
3 years ago
12

A triangle with vertices labeled as X, Y, and Z. Side X Z is base. Side Y X contains a midpoint M. A line segment drawn from Z t

o M bisects angle Y Z X into two parts labeled as Y Z M and X Z M. Angles Y Z M and X Z M are marked with single arc. Side Y Z is labeled 7. Base X Z is labeled 11. Side Y M is labeled 3.5.

Mathematics
1 answer:
MakcuM [25]3 years ago
3 0

Answer:

The value of MX is 5.5 units.

Step-by-step explanation:

As the complete question is not given, the complete question is found online and is attached herewith

brainly.com/question/11944039

The diagram is attached with the solution.

As the line ZM is dividing the angle in two parts thus as the two angles are equal thus

The sides are given as

XZ=11

YM=3.5

YZ=7

Now by the theorem of the angles, the bisected angles are such that sin(<YZM)=sin(<XZM)

so

sin(

So the value of MX is 5.5 units.

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Lerok [7]

Answer:

c. 1 \frac{3}{8} inches

Step-by-step explanation:

Since the paper clip is past the 1, the answer will be 1 and ___.

the mark in the middle of the 1 and 2 is one half (1/2)

the mark in between the 1 and 1/2 is 1/4

the mark between 1/4 and 1/2 is 1/8

there are three (3) 1/8 marks where the paperclip is

3 * 1/8 = 3/8

so your answer is 1 3/8

hope this helps:)

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2 years ago
The more surface area an ice cube has, the more quickly it melts to cool a beverage. mark states that the ideal ice cube would b
Ber [7]
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5 0
4 years ago
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Find the measure of the angle indicated. Assume that lines which appear tangent are tangent.
Tanzania [10]

Answer:

D. 69°

Step-by-step explanation:

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3 0
3 years ago
Right answer gets brainlist.
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7 0
3 years ago
For the data set 6,5,10,11,13, the mean, x, is 9. What is the standard deviation?
Ratling [72]

Answer:

3.39

Step-by-step explanation:     

We will use SD formula to find our answer.

\sigma=\sqrt{ \frac{\sum (x-\overline{x})^{2}}{N-1} }

\sigma= Standard deviation.

\overline{x}= Mean.

N= Numbers of data-points.

We have been given that mean of our data set is 9. So we will find the square of each data point's distance to the mean.

Now let us substitute our given values in above formula.

\sigma=\sqrt{ \frac{(6-9)^{2}+(5-9)^{2}+(10-9)^{2}+(11-9)^{2}+(13-9)^{2}}{5-1} }

\sigma=\sqrt{ \frac{(-3)^{2}+(-4)^{2}+(1)^{2}+(2)^{2}+(4)^{2}}{4} }

Upon adding the square of distances we will get,  

\sigma=\sqrt{ \frac{9+16+1+4+16}{4} }

\sigma=\sqrt{ \frac{46}{4} }

Upon dividing 46 by 4 we will get,

\sigma=\sqrt{ 11.5}

Upon taking square root of 11.5 we will get,

\sigma=3.3911649915626341\approx 3.39

Therefore, the standard deviation for our given data set will be 3.39.  

3 0
3 years ago
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