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gladu [14]
2 years ago
12

A triangle with vertices labeled as X, Y, and Z. Side X Z is base. Side Y X contains a midpoint M. A line segment drawn from Z t

o M bisects angle Y Z X into two parts labeled as Y Z M and X Z M. Angles Y Z M and X Z M are marked with single arc. Side Y Z is labeled 7. Base X Z is labeled 11. Side Y M is labeled 3.5.

Mathematics
1 answer:
MakcuM [25]2 years ago
3 0

Answer:

The value of MX is 5.5 units.

Step-by-step explanation:

As the complete question is not given, the complete question is found online and is attached herewith

brainly.com/question/11944039

The diagram is attached with the solution.

As the line ZM is dividing the angle in two parts thus as the two angles are equal thus

The sides are given as

XZ=11

YM=3.5

YZ=7

Now by the theorem of the angles, the bisected angles are such that sin(<YZM)=sin(<XZM)

so

sin(

So the value of MX is 5.5 units.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Solve for x 0=3x^2+3x+7​
Aloiza [94]

Answer:

x =(3-√-75)/-6=1/-2+5i/6√ 3 = -0.5000-1.4434i

x =(3+√-75)/-6=1/-2-5i/6√ 3 = -0.5000+1.4434i

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    0-(3*x^2+3*x+7)=0

Step by step solution:

Step  1:

Equation at the end of step  1  :

 0 -  ((-3x^{2} +  3x) +  7)  = 0  

<u>Step  2:</u>

Pulling out like terms:

2.1     Pull out like factors:

  -3x^{2} - 3x - 7  =   -1 • (3x^{2} + 3x + 7)

Trying to factor by splitting the middle term

2.2     Factoring  3x^{2} + 3x + 7

The first term is,  3x^{2}  its coefficient is  3 .

The middle term is,  +3x  its coefficient is  3 .

The last term, "the constant", is  +7

Step-1 : Multiply the coefficient of the first term by the constant   3 • 7 = 21

Step-2 : Find two factors of  21  whose sum equals the coefficient of the middle term, which is   3 .

     -21    +    -1    =    -22

     -7    +    -3    =    -10

     -3    +    -7    =    -10

     -1    +    -21    =    -22

     1    +    21    =    22

     3    +    7    =    10

     7    +    3    =    10

     21    +    1    =    22

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step  3  :

 -3x^{2} - 3x - 7  = 0

<u>Step  3:</u>

Parabola, Finding the Vertex:

3.1      Find the Vertex of   y = -3x^{2}-3x-7

For any parabola,Ax2+Bx+C,the  x -coordinate of the vertex is given by  -B/(2A) . In our case the  x  coordinate is  -0.5000  

Plugging into the parabola formula  -0.5000  for  x  we can calculate the  y -coordinate :

 y = -3.0 * -0.50 * -0.50 - 3.0 * -0.50 - 7.0

or   y = -6.250

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = -3x^{2}-3x-7

Axis of Symmetry (dashed)  {x}={-0.50}

Vertex at  {x,y} = {-0.50,-6.25}

Function has no real roots

Solve Quadratic Equation by Completing The Square

3.2     Solving   -3x^{2}-3x-7 = 0 by Completing The Square .

Multiply both sides of the equation by  (-1)  to obtain positive coefficient for the first term:

3x^{2}+3x+7 = 0  Divide both sides of the equation by  3  to have 1 as the coefficient of the first term :

  x^{2}+x+(7/3) = 0

Subtract  7/3  from both side of the equation :

  x^{2}+x = -7/3

Now the clever bit: Take the coefficient of  x , which is  1 , divide by two, giving  1/2 , and finally square it giving  1/4

Add  1/4  to both sides of the equation :

 On the right hand side we have :

  -7/3  +  1/4   The common denominator of the two fractions is  12   Adding  (-28/12)+(3/12)  gives  -25/12

 So adding to both sides we finally get :

  x^{2}+x+(1/4) = -25/12

Adding  1/4  has completed the left hand side into a perfect square :

  x^{2}+x+(1/4)  =

  (x+(1/2)) • (x+(1/2))  =

 (x+(1/2))2

Things which are equal to the same thing are also equal to one another. Since

  x^{2}+x+(1/4) = -25/12 and

  x^{2}+x+(1/4) = (x+(1/2))2

then, according to the law of transitivity,

  (x+(1/2))2 = -25/12

We'll refer to this Equation as  Eq. #3.2.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

  (x+(1/2))2   is

  (x+(1/2))2/2 =

 (x+(1/2))1 =

  x+(1/2)

Now, applying the Square Root Principle to  Eq. #4.2.1  we get:

  x+(1/2) = √ -25/12

Subtract  1/2  from both sides to obtain:

  x = -1/2 + √ -25/12

 √ 3   , rounded to 4 decimal digits, is   1.7321

So now we are looking at:

          x  =  ( 3 ± 5 •  1.732 i ) / -6

Two imaginary solutions :

x =(3+√-75)/-6=1/-2-5i/6√ 3 = -0.5000+1.4434i

 or:

x =(3-√-75)/-6=1/-2+5i/6√ 3 = -0.5000-1.4434i

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