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inysia [295]
4 years ago
6

Which is an acceptable Lewis structure for a diatomic nitrogen molecule?

Chemistry
1 answer:
madam [21]4 years ago
7 0
Https://quizlet.com/18404690/chemistry-final-flash-cards/ 

here  is a Quizlet I have for that

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The total volume in milliliters of a glucose-water solution is given by the equation below: V = 1001.93 + 111.5282m + 0.64698m^2
vagabundo [1.1K]

Answer:

a. Vₐ = 111.5282 + 1.29396m

b. For m = 0.100m; Vₐ = 111.6576

Explanation:

The partial molar volume of compound A in a mixture of A and B is defined as :

V_a = \frac{dV}{dn_a}

Where V is volume and n are moles of a.

a. As molality is proportional to moles of substance, partial molar volume of glucose can be defined as:

Vₐ =  dV / dm =  d(1001.93 + 111.5282m + 0.64698m²) / dm

<em>Vₐ = 111.5282 + 1.29396m</em>

b. Replacing for m = 0.100m:

Vₐ = 111.5282 + 1.29396×0.100

<em>Vₐ = 111.6576</em>

<em></em>

I hope it helps!

3 0
3 years ago
Organisms such as grass and lichens are classified as
mash [69]

I think the answer is producers

I hope that helped and have a nice day!! (:

3 0
3 years ago
The equilibrium concentrations of the reactants and products are [ HA ] = 0.260 M [HA]=0.260 M , [ H + ] = 2.00 × 10 − 4 M [H+]=
ValentinkaMS [17]

Answer:

pKa of the acid HA with given equilibrium concentrations is 6.8

Explanation:

The dissolution reaction is:

HA ⇔ H⁺ + A⁻

So at equilibrium, Ka is calculated as below

Ka = [H⁺] x [A⁻] / [HA] = 2.00 x 10⁻⁴ x 2.00 x 10⁻⁴ / 0.260

    = 15.38 x 10⁻⁸

Hence, by definition,

pKa = -log(Ka) = - log(15.38 x 10⁻⁸) = 6.813

7 0
3 years ago
Balance this equation. Not all spots have to have a number.
Lisa [10]

2Na+2H2O----2NaOH+H2

3 0
3 years ago
Octopus and squids breathe through
svet-max [94.6K]

<em>Octopus and squids breathe</em> <em>like </em><em>fishes </em><em>they </em><em>breathe </em><em>from </em><em>gills </em>

<em>so </em><em>even </em><em>octopus</em><em> and</em><em> squids</em><em> </em><em>breathe </em><em>through </em><em>gills </em><em>too.</em>

<em><u>maybe </u></em><em><u>this </u></em><em><u>answer</u></em><em><u> </u></em><em><u>would</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em>

4 0
3 years ago
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