Answer:
a. Vₐ = 111.5282 + 1.29396m
b. For m = 0.100m; Vₐ = 111.6576
Explanation:
The partial molar volume of compound A in a mixture of A and B is defined as
:

Where V is volume and n are moles of a.
a. As molality is proportional to moles of substance, partial molar volume of glucose can be defined as:
Vₐ = dV / dm = d(1001.93 + 111.5282m + 0.64698m²) / dm
<em>Vₐ = 111.5282 + 1.29396m</em>
b. Replacing for m = 0.100m:
Vₐ = 111.5282 + 1.29396×0.100
<em>Vₐ = 111.6576</em>
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Answer:
pKa of the acid HA with given equilibrium concentrations is 6.8
Explanation:
The dissolution reaction is:
HA ⇔ H⁺ + A⁻
So at equilibrium, Ka is calculated as below
Ka = [H⁺] x [A⁻] / [HA] = 2.00 x 10⁻⁴ x 2.00 x 10⁻⁴ / 0.260
= 15.38 x 10⁻⁸
Hence, by definition,
pKa = -log(Ka) = - log(15.38 x 10⁻⁸) = 6.813
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