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2 years ago

What is the relationship between mass, distance and gravity?

Chemistry

1 answer:

romanna [79]2 years ago

6 0

Answer:

Mass is the measure of the amount of matter in an object. We see that the gravitational force between objects increases as the masses of the objects increase. With distance, we see that the strength of gravity decreases if the distance between two objects increases.

Explanation:

The amount of gravity affecting an object depends on two things: the masses of the objects being attracted and the distance between the objects. Mass is the measure of the amount of matter in an object. ... With distance, we see that the strength of gravity decreases if the distance between two objects increases

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If an acid or alkali is diluted by a factor of 10, what effect will this have on its pH?

Alisiya [41]

Answer: When an acidic solution is diluted with water the concentration of H + ions decreases and the pH of the solution increases towards 7.

Explanation:

5 0

2 years ago

A 350.0 ml sample of gas has a temperature of 22.7 C and a pressure of 0.914 atm. What temperature would be needed for the same

Rus_ich [418]

Answer:

Explanation:

We shall apply gas law formula

P₁ V₁ / T₁ = P₂V₂ / T₂

.914 x 350 / ( 273 + 22.7 ) = 1 x 220 / T₂

1.0818 = 220 / T₂

T₂ = 203.36 K

= - 69.64 ⁰ C

7 0

3 years ago

Using words, explain all steps of dimensional analysis when converting 6.7 hectometers to meters. You must explain the set up of

sleet_krkn [62]

Answer:

See below

Explanation:

In order to convert 6.7 hectometers to meters using dimensional analysis, you must use the ratio of hectometers to meters.

There are 100 meters in one hectometer, then you start setting the equality: 100 m = 1 hm.

Dividing both sides by 1 hm you get the fraction form of the ratio, with meters (m) in the numerator and hectometers (hm) in the denominator.

$1m/100hm$

Since hm is in the numerator, when you multiply 6.7 hm by the unit ratio the hm will be canceled and the result will have only m:

$6.7hm\times 1m/100hm=0.067m$

6 0

3 years ago

Calculate the mass of water vapour present in a room of volume 400 m3 that contains air at 27 °C on a day when the relative humi

Alex73 [517]

Answer:

Mass of water = 6251. 706g or 6.25Kg

Explanation:

Relative humidity = (actual vapor pressure/saturation vapor pressure) * 100%

Actual vapor pressure, Pw = relative humidity * saturation vapor pressure

Pw = 60% * (35.6 *0.001)atm = 0.0216atm

Note: 1mbar = 0.001atm

Using the ideal gas equation: PV=nRT; where P = Pw= 0.02136atm, V= (400

* 1000)dm^3, R= 0.082 atmdm^3/kmol, T= (27+273)K, n = number of moles

Note: 1m^3 = 1000dm^3,R is the molar gas constant.

Making n subject of the formula, n = PV/RT

n= (0.02136 * 400000)/(0.082 * 300) = 347.317 moles

Mass (g) = number of moles (n) * molar mass

molar mass of water=18g

Mass of water = 347.317 * 18 = 6251. 706g or 6.25Kg

6 0

3 years ago

Need help this question QUICK

tino4ka555 [31]

The answer is number 2

4 0

3 years ago