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Mademuasel [1]
3 years ago
10

You push a 1.00 food tray through the cafeteria One

Physics
1 answer:
lawyer [7]3 years ago
7 0

Answer:

Acceleration of tray and carton = 6.03 m/s²

Horizontal force exerted by tray in carton = 3.02 N

Explanation:

Given:

Mass of tray (M) = 1.00 kg

Mass of milk carton (m) = 0.50 kg

Force applied on the system (F) = 9.04 N

The tray and carton slide horizontally without friction.

The free body diagram of the system is shown below.

The net force acting on the tray and carton system is the constant force 9.04 N.

The total mass of the system is (M + m) = 1.00 kg + 0.50 kg = 1.50 kg

Now, according to Newton's second law:

Net Force = mass × acceleration

⇒ Acceleration = Net force ÷ mass

Therefore, the acceleration of the tray and carton is given as:

a=\frac{9.04}{1.50}=6.03\ m/s^2

Now, consider the free body diagram of the carton alone.

The forces acting on the carton is only the horizontal force (f) exerted by the tray.

So, from Newton's second law:

Net Force = mass × acceleration

f=ma\\f=0.50\times 6.03\\f=3.02\ N

Therefore, the horizontal force exerted by the tray on the carton is 3.02 N.

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The scale in N, reading if the elevator moves upward at a constant speed of 1.5 m/s^2 is 862.5 N.

weight of man = 75kg

speed of elevator, a = 1.5 m/ s^{2}

F - w = ma \\

F = w + ma

F = m ( a +g )

F = 75 ( 1.5 + 10 ) \\

F = 75 ( 11.5 )

F = 862.5 N

So, the scale reading in the elevator is greater than his 862.5 N weight. This indicates that the person is being propelled upward by the scale, which it must do in order to do so, with a force larger than his weight. According to what you experience in quickly accelerating or slowly moving elevators, it is obvious that the faster the elevator acceleration, the greater the scale reading.

Speed can be defines as the pace at which the position of an object changes in any direction.  Since speed simply has a direction and no magnitude, it is a scalar quantity.

Learn more about speed here:-

brainly.com/question/19127881

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describe at least two ways in which parents are able to influence the drinking habits of their children
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A 100 N force is applied to a 50 kg crate resting on a level floor. The coefficient of kinetic friction is 0.15. What is the acc
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The acceleration of the crate after it begins to move is 0.5 m/s²

We'll begin by calculating the the frictional force

Mass (m) = 50 Kg

Coefficient of kinetic friction (μ) = 0.15

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) = mg = 50 × 10 = 500 N

<h3>Frictional force (Fբ) =?</h3>

Fբ = μN

Fբ = 0.15 × 500

<h3>Fբ = 75 N</h3>

  • Next, we shall determine the net force acting on the crate

Frictional force (Fբ) = 75 N

Force (F) = 100 N

<h3>Net force (Fₙ) =?</h3>

Fₙ = F – Fբ

Fₙ = 100 – 75

<h3>Fₙ = 25 N</h3>

  • Finally, we shall determine the acceleration of the crate

Mass (m) = 50 Kg

Net force (Fₙ) = 25 N

<h3>Acceleration (a) =?</h3>

a = Fₙ / m

a = 25 / 50

<h3>a = 0.5 m/s²</h3>

Therefore, the acceleration of the crate is 0.5 m/s²

Learn more on friction: brainly.com/question/364384

8 0
2 years ago
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