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3 years ago

You push a 1.00 food tray through the cafeteria One

Physics

1 answer:

lawyer [7]3 years ago

7 0

Answer:

Acceleration of tray and carton = 6.03 m/s²

Horizontal force exerted by tray in carton = 3.02 N

Explanation:

Given:

Mass of tray (M) = 1.00 kg

Mass of milk carton (m) = 0.50 kg

Force applied on the system (F) = 9.04 N

The tray and carton slide horizontally without friction.

The free body diagram of the system is shown below.

The net force acting on the tray and carton system is the constant force 9.04 N.

The total mass of the system is (M + m) = 1.00 kg + 0.50 kg = 1.50 kg

Now, according to Newton's second law:

Net Force = mass × acceleration

⇒ Acceleration = Net force ÷ mass

Therefore, the acceleration of the tray and carton is given as:

$a=\frac{9.04}{1.50}=6.03\ m/s^2$

Now, consider the free body diagram of the carton alone.

The forces acting on the carton is only the horizontal force (f) exerted by the tray.

So, from Newton's second law:

Net Force = mass × acceleration

$f=ma\\f=0.50\times 6.03\\f=3.02\ N$

Therefore, the horizontal force exerted by the tray on the carton is 3.02 N.

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To understand how to find the velocities of objects after a collision.

trasher [3.6K]

There are some information missing on Part D: Let the mass of object 1 be m and the mass of object 2 be 3m. If the collision is perfectly inelastic, what are the velocities of the two objects after the collision? Give the velocity v_1 of object one, followed by object v_2 of object two, separated by a comma. Express each velocity in terms of v.

Answer: Part A: v_1 = 0; v_2 = v

Part B: v_1 = v_2 = $\frac{v}{2}$

Part C: v_1 = $\frac{v}{3}$ ; v_2 = $\frac{4v}{3}$

Part D: v_1 = v_2 = $\frac{v}{4}$

Explanation: In elastic collisions, there no loss of kinetic energy and momentum is conserved. Momentum is determined as p = m.v and kinetic energy as K = $\frac{1}{2}$ m. $v^{2}$

Conserved means that the amount of initial momentum is equal to the amount of final momentum:

$m_{1}$ . $v_{1i}$ + $m_{2}$ . $v_{2i}$ = $m_{1}.v_{1f} + m_{2}.v_{2f}$

No loss of energy means that initial kinietc energy is the same as the final kinetic energy:

$\frac{1}{2}(m_{1}.v_{1i} + m_{2}.v_{2i}) = \frac{1}{2} (m_{1}.v_{1f} + m_{2}.v_{2f} )$

To determine the final velocities of each object, there are 2 variables and two equations, so working those equations, the result is:

$v_{2f} = \frac{2.m_{1} } {m_{1} + m_{2} }.v_{1i} + \frac{(m_{2} - m_{1})}{m_{1} + m_{2} } . v_{2i}$

$v_{1f} = \frac{m_{2} - m_{1} }{m_{1} + m_{2} } . v_{1i} + \frac{2.m_{2} }{m_{1} + m_{2} } .v_{2i}$

For all the collisions, object 2 is static, i.e. $v_{2i}$ = 0

Part A: Both objects have the same mass (m), $v_{1i}$ = v and collision is elastic:

v_1 = $\frac{m_{2} - m_{1}}{m_{1} + m_{2} } . v_{1i}$

v_1 = 0

v_2 = $\frac{2.m_{1} }{m_{1} + m_{2}}.v_{1i}$

v_2 = $\frac{2.m}{m+m}.v$

v_2 = v

When the masses are the same and there is an object at rest, the object in movement stops and the object at rest has the same same velocity as the object who hit it.

Part B: Same mass but collision is inelastic: An inelastic collision means that after it happens, the two objects has the same final velocity, then:

$m_{1}$ . $v_{1i}$ + $m_{2}$ . $v_{2i}$ = $m_{1}.v_{1f} + m_{2}.v_{2f}$

$m_{1}.v_{1i} = (m_{1}+m_{2}).v_{f}$

$v_{f} = \frac{m_{1}.v_{1i}}{m_{1} + m_{2} }$

v_1 = v_2 = $\frac{m.v}{m+m}$

v_1 = v_2 = $\frac{v}{2}$

Part C: Object 1 is 2m, object 2 is m and elastic collision:

v_1 = $\frac{m_{2} - m_{1}}{m_{1} + m_{2} } . v_{1i}$

v_1 = $\frac{2m - m}{2m + m } . v$

v_1 = $\frac{v}{3}$

v_2 = $\frac{2.m_{1} }{m_{1} + m_{2}}.v_{1i}$

v_2 = $\frac{2.2m}{2m+m}.v$

v_2 = $\frac{4v}{3}$

Part D: Object 1 is m, object is 3m and collision is inelastic:

v_1 = v_2 = $v_{f} = \frac{m_{1}.v_{1i}}{m_{1} + m_{2} }$

v_1 = v_2 = $\frac{m}{m+3m}.v$

v_1 = v_2 = $\frac{v}{4}$

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Two parallel plates of area 0.155 m2 are separated by 0.00100 m. What is their capacitance?

KonstantinChe [14]

Answer:

1.37 x 10^-9

Explanation:

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How many million kilometers is one astronomical unit.

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Answer:

150 million kilometres

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2 years ago

Measurements of acceleration are given in units of ?

Lady_Fox [76]

Meters per second squared: $\frac{m}{s^{2}}$

If you think about it, acceleration is about how fast speed changes. Speed is measured in meters per second: $\frac{m}{s}$

So if you take that and just measure it over time, you get meters per second squared.

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3 years ago

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________ is an arrhythmia in which there is a very fast but regular rhythm (250 beats per minute) of the atria or ventricles.

erastova [34]

Answer:

Flutter

Explanation:

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Arrhythmia can be defined as any sort of irregularity heart rate or rhythm is also called as dysrhythmia.

Arrhythmias can be categorized as heart block, bradycardia, tachycardia, fibrillation, flutter, sick sinus syndrome, and is diagnosed by Electrocardiography.

In Flutter, the heart chambers do get sufficient time to get filled with blood completely prior to next contraction.

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