Answer: C
Explanation: I guessed, don’t hurt me
Answer:
I believe it's false. Why would it increase?
Explanation:
Answer:
Fc = 89.67N
Explanation:
Since the rope is unstretchable, the total length will always be 34m.
From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:
L1+L2=34m
Replacing this value in the previous equation:
Solving for H:
We can now, calculate the angle between L1 and the 2m segment:
If we make a sum of forces in the midpoint of the rope we get:
where T is the tension on the rope and F is the exerted force of 87N.
Solving for T, we get the tension on the rope which is equal to the force exerted on the car:
Answer:
The total kinetic energy of the system before the collision is 57 Joules.
Explanation:
Given that,
Mass of first block,
Speed of first block,
Mass of second block,
Speed of first block,
We need to find the total kinetic energy of the system before the collision. It is equal to the kinetic energies of both the blocks. It is given by :
So, the total kinetic energy of the system before the collision is 57 Joules.
Answer:
the kinetic energy of A will be twice that of B
Explanation:
The formula for calculating kinetic energy is expressed using the formula
KE = 1/2mv²
m is the mass of the object
v is the velocity
For object A:
KEA = 1/2mAvA²
For object B:
KEB = 1/2mBvB² ... 1
If object A is twice the mass of object B, then mA = 2mB
From 1:
KEA = 1/2mAvA²
Substitute mA = 2mB
KEA = 1/2(2mB)vA² .... 2
Divide 1 by 2
KEB/KEA = 1/2mBvB²/mBvA²
KEB/KEA = 1/2vB²/vA²
Assuming they have the same velocities then vA ,= VB
The equation becomes:
KEB/KEA = 1/2vB²/vA²
KEB/KEA = 1/2vB²/vB²
KEB/KEA = 1/2
KEA = 2EB
Hence the kinetic energy of A will be twice that of B