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ICE Princess25 [194]

2 years ago

14

Air spaces are used in insulation because _____. air is a good conductor air is a poor conductor air is light air is colorless U

ser: What will happen as an object receives energy due to heat flow?

2 answers:

Mariulka [41]2 years ago

4 0

Air spaces are used in insulation because air is a poor conductor.

Serhud [2]2 years ago

4 0

Answer: The correct answer is "air is a poor conductor".

Explanation:

Air is a mixture of gases. The amount of heat that can be transferred is minimal through air.

Air is an insulator. Insulator is used to control and slow the transfer of energy from the warmer objects to cooler objects. Air is a bad conductor.

Conductors allow the energy to flow while an insulator stops the flow of energy.

The wool traps air against your body as both wool and air are poor conductor.

Therefore, Air spaces are used in insulation because air is a poor conductor.

when an object receives energy due to heat flow then the kinetic energy of the particles of the object increases because the kinetic energy and the temperature are directly proportional to each others. When heat is added to the object then the movement of the particles increases.

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Which of the following statements are true? I. The number of protons in an element is the same for all neutral atoms of that ele

FromTheMoon [43]

Answer:

Both statements I, and II are true

Explanation:

I)One is true.The number of protons of the element is the defining characteristic of it. This is, if we take a proton or add a proton to a nucleus we will be changing the element. Therefore, the number of protons is the same for all neutral and not neutral atoms of that element.

II)Two is true. If an atom is neutral, it will have the same number of electrons and protons. As the number of protons for an element cannot change (see I), then the number of electrons will be the same for all neutral atoms of this element.

III)Three is false. We can have a neutral atoms of the same element with different number of neutrons, as neutrons do not change the charge of the atom(they change their mass, though). These are called Isotopes.

6 0

2 years ago

The heating element of a water heater in an apartment building has a maximum power output of 37 kW. Four residents of the buildi

kkurt [141]

Answer:

maximum possible temperature is 34.088°C

Explanation:

Given data

power output Q = 37 kW

volume flow rate = 11 x 10^-5 m3/s

temperature t = 14°C

to find out

maximum possible temperature T

solution

we can say

total water volume = 4 residents × volume flow

total water volume = 4 × 11 x 10^-5 = 44 × 10^-5 m³/s

so we say total water mass = 1000 × volume

total water mass = 1000 kg/m³ × 44 × 10^-5

total water mass = 0.44 kg

we know

dQ/dt = (dm/dt)× (S)× ( T - t)

so here we know specific heat of water S = 4.186 joule/gram °C

37 = 0.44 × 4.186 × (T-14)

T = 34.088°C

maximum possible temperature is 34.088°C

3 0

2 years ago

5) What is the net force caused by the moon acting on earth when the moon is 3.86x10^8 m away? The moon has a mass of 7.46x10^23

Dimas [21]

Answers:

5) $1.99(10)^{21} N$

6) $1.37(10)^{18} N$

7) $1.64(10)^{21} N$

8) $4.29(10)^{10} N$ more than Venus force of gravity on Pluto

Explanation:

According to Newton's law of Universal Gravitation, the force $F$ exerted between two bodies of masses $M$ and $m$ and separated by a distance $R$ is equal to the product of their masses and inversely proportional to the square of the distance:

$F=G\frac{Mm}{R^{2}}$ (1)

Where $G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the Gravitational Constant

This is the equation we will use to solve each question in this problem.

<h3>5) Gravitational force between Earth and Moon</h3>

In this case we have:

$F_{earth-moon}$ is the gravitational force between Earth and Moon

$M=5.97(10)^{24} kg$ is the mass of the Earth

$m=7.46(10)^{23} kg$ is the mass of the Moon

$R=3.86(10)^{8} m$ is the distance between Earth and Moon

Solving:

$F_{earth-moon}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(5.97(10)^{24} kg)(7.46(10)^{23} kg)}{(3.86(10)^{8} m)^{2}}$ (2)

$F_{earth-moon}=1.99(10)^{21} N$ (3)

<h3>6) Gravitational force between Jupiter and Venus</h3>

Assuming for a moment that the planets are perfectly aligned and all are in the same orbital period, we can make a rough estimation of the distance between Jupiter and Venus, knowing the distance of each to the Sun:

distance between Sun and Jupiter - distance between Sun and Venus=distance between Jupiter and Venus= $R_{jupiter-venus}$ (4)

$R_{jupiter-venus}=778.3(10)^{9} m - 108(10)^{9} m=6.703(10)^{11} m$ (5)

Using this value in the Law of Universal Gravitation equation:

$F_{jupiter-venus}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.90(10)^{27} kg)(4.87(10)^{24} kg)}{(6.703(10)^{11} m)^{2}}$ (6)

$F_{jupiter-venus}=1.37(10)^{18} N$ (7)

<h3>7) Gravitational force between Saturn and Mars</h3>

Using the same assumption we made in the prior question:

distance between Sun and Saturn - distance between Sun and Mars=distance between Saturn and Mars= $R_{saturn-mars}$ (8)

$R_{saturn-mars}=1427(10)^{9} m - 227.9(10)^{9} m=227.9(10)^{9} m$ (9)

Using this value in the Law of Universal Gravitation equation:

$F_{saturn-mars}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.989(10)^{30} kg)(6.42(10)^{23} kg)}{(227.9(10)^{9} m)^{2}}$ (10)

$F_{saturn-mars}=1.64(10)^{21} N$ (11)

<h3>8) How much more is earths force of gravity on Pluto than Venus force of gravity on Pluto?</h3>

Firstly, we need to find $F_{earth-pluto}$ and then find $F_{venus-pluto}$ in order to find the difference.

<u>For $F_{earth-pluto}$ :</u>

$M=5.97(10)^{24} kg$ is the mass of the Earth

$m=1.46(10)^{22} kg$ is the mass of Pluto

$R_{earth-pluto}=5.7504(10)^{12} m$ is the distance between Earth and Pluto

$F_{earth-pluto}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(5.97(10)^{24} kg)(1.46(10)^{22} kg)}{(5.7504(10)^{12} m)^{2}}$ (12)

$F_{earth-pluto}=1.759(10)^{11} N$ (13) Force between Earth and Pluto

<u></u>

<u>For $F_{venus-pluto}$ :</u>

$M=4.87(10)^{24} kg$ is the mass of Venus

$m=1.46(10)^{22} kg$ is the mass of Pluto

$R_{venus-pluto}=5.792(10)^{12} m$ is the distance between Venus and Pluto

$F_{venus-pluto}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(4.87(10)^{24} kg)1.46(10)^{22} kg)}{(5.792(10)^{12} m)^{2}}$ (14)

$F_{venus-pluto}=1.33(10)^{11} N$ (15) Force between Venus and Pluto

Calculating the difference:

$F_{earth-pluto}-F_{venus-pluto}=1.759(10)^{11} N-1.33(10)^{11} N$

Finally:

$F_{earth-pluto}-F_{venus-pluto}=4.29(10)^{10} N$ (16)

Hence:

Earths force of gravity on Pluto is $4.29(10)^{10} N$ than Venus force of gravity on Pluto.

3 0

2 years ago

The density of a fish tank is 0.2fish over feet cubed. There are 8 fish in the tank. What is the volume of the tank?

Verizon [17]

Density is a physical property which describes the mass of a substance per unit of volume of the substance. It is expressed as Density = m / V and it has units like g/cm^3. We use the density given to solve the problem.

<span> Volume of the tank = 8 fishes / 0.2 fish / ft</span><span>³</span>

<span>Volume of the tank = 40 ft</span><span>³</span>

8 0

2 years ago

What is a proton?

eimsori [14]

The answer is A. A positive particle inside the nucleus

7 0

2 years ago

Read 2 more answers