Answer:
75 N
Explanation:
In this problem, the position of the crate at time t is given by
The velocity of the crate vs time is given by the derivative of the position, so it is:
Similarly, the acceleration of the crate vs time is given by the derivative of the velocity, so it is:
[m/s^2]
According to Newton's second law of motion, the force acting on the crate is equal to the product between mass and acceleration, so:
where
m = 5.00 kg is the mass of the crate
At t = 4.10 s, the acceleration of the crate is
And therefore, the force on the crate is:
The topic here is momentum.
When a collision is said to be elastic, it means that the colliding objects now travel at their own new, indivual and distinct velocities, often in different directions.
So we write that as,
(mass of football player x velocity of football player) + (mass of referee x velocity of referee) = (mass of football player x velocity of football player) + (mass of referee x velocity of referee)
(M × 8) + (80 × 0) = (M× 0) + (80 × 5)
8M = 400
M = 50 kg
Answer:
the answer is A, 9.5 units
Answer:
d. Increase the velocity of the ride and decrease the radius
Explanation:
The normal force in the amusement park ride is produced by the centripetal force. The formula for this force is given as follows:
Fn = mv²/r
where,
m = mass of the body,
v = velocity of the body
r = radius of the path
Therefore, it is clear from the formula that force has a direct relation with the square of velocity and inverse relation with the radius of path. Hence, the design that will enable the rider to feel the greatest Fn will be:
<u>d. Increase the velocity of the ride and decrease the radius</u>
