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2 years ago

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A balloon with a volume of 2.0 l at 25°c is placed in a hot room at 35°c. the pressure on the balloon is constant at 1.0 atm. fo

rmula to use: v1 t1 = v2 t2 how does the volume of the balloon change after moving it to the hot room?

2 answers:

shusha [124]2 years ago

5 0

The volume increases and the final volume is 2.1 L

<h3>Why volume increases?</h3>

The volume of a gas is directly related to the heat and pressure. If temperature increases, volume increases.

If pressure increases, volume decreases

Based on Boyle's law,

The absolute temperature of a gas is directly proportional to the volume of the gas.

As the balloon change increases its temperature, the volume increases

The Boyle's equation is:

V₁T₂ = V₂T₁

Where,

V is volume
T is absolute temperature of 1, initial state and 2, final state of the gas.

Replacing :

V₁ = 2.0L

T₂ = 35°C + 273.15 = 308.15K

V₂ = ?

T₁ = 25°C + 273.15 = 298.15 K

2.0L x 308.15 K = V₂ x 298.15 K

2.1 L = V₂

Final volume is 2.1L

Hence, The volume increases and the final volume is 2.1 L

Learn more about gas laws here ;

brainly.com/question/12669509

#SPJ1

Archy [21]2 years ago

4 0

Answer:

increases, 2.1

Explanation:

I got it right.

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