Answer:
ΔU =195 KJ
W=0 KJ
Explanation:
Given that
Mass of air m=3 kg
heat absorb by air =195 KJ
Cv=0.741 KJ/kgK
If we assume that air is as ideal gas so
Given that container is rigid it means that volume of system is constant so W=0
From first law of thermodynamics
Q=ΔU + W
⇒Q= ΔU (W=0)
So ΔU =195 KJ
And work done will be zero because because it is a constant volume process.
Answer:
- 1.55
- 260 N.s
- 3370 m
- 1.6
- 43.75 kg/s
Explanation:
1) Thrust coefficient at sea level.
Cfsl = TSL / Pca
TSL = Mp * Vc + ( Pc - Pa )Ac
Mp = mass flux = 43.75 kg/s
∴ Cfsl = Mp Vc / Pca + ( Pc - Pa )/Pc * ( Ac / A* )
= 1.6 - 0.04923 = 1.55
<u>2) Specific impulse at sea </u>
Isp = Vc / g = 2549.75 / 9.81
= 260 N.s
3) Altitude at optimal expansion
H = 3370 m
<u>4) thrust coefficient at optimal expansion </u>
CF = 1.6
attached below is the detailed solution
<u>5) Mass flux through the throat </u>
Mass flux = P1 * At / Cc
= ( 7*10^6 * 0.01 ) / 1600
= 43.75 kg/s
Answer:
New electric field = 18 N/C
Explanation:
Given:
Length (E1) = 2 cm
New length (E2) = 4 cm
Electric field = 36 N/C
Find:
New electric field
Computation:
New electric field = 36 [2 / 4]
New electric field = 36 [1/2]
New electric field = 18 N/C
Answer:
The transistor will be in amplifier mode and we will expect current will be higher than expected.