To solve this problem we will apply the concepts of speed given the simple harmonic movement, for which it defines this speed as
Here
Angular velocity
A = Amplitude
Recall that the angular velocity is equivalent in terms of the frequency at
If we replace the value we will have then
<em>For mass A </em>
<em>For mass B </em>
Therefore they are equal.
Answer:
A change in pressure
Explanation:
This is because, the deeper you dive, the height of water above you creates a pressure on you. So, as the depth increases, the height of water increases, thus its weight on you, thus its pressure on you also.
Also, as you gain altitude as you climb a mountain, the height of air above you decreases. This thereby decreases the weight of air above you thus, decreasing the pressure of air on you.
So, in both cases, there is a change in pressure as height or depth changes. An increase in height results in decreased pressure and an increases in depth results in increased pressure.
Answer:
Displacement is fundamental unit
Answer:
28.5 m/s
18.22 m/s
Explanation:
h = 20 m, R = 20 m, theta = 53 degree
Let the speed of throwing is u and the speed with which it strikes the ground is v.
Horizontal distance, R = horizontal velocity x time
Let t be the time taken
20 = u Cos 53 x t
u t = 20/0.6 = 33.33 ..... (1)
Now use second equation of motion in vertical direction
h = u Sin 53 t - 1/2 g t^2
20 = 33.33 x 0.8 - 4.9 t^2 (ut = 33.33 from equation 1)
t = 1.17 s
Put in equation (1)
u = 33.33 / 1.17 = 28.5 m/s
Let v be the velocity just before striking the ground
vx = u Cos 53 = 28.5 x 0.6 = 17.15 m/s
vy = uSin 53 - 9.8 x 1.17
vy = 28.5 x 0.8 - 16.66
vy = 6.14 m/s
v^2 = vx^2 + vy^2 = 17.15^2 + 6.14^2
v = 18.22 m/s
Answer:
The radius of the sphere is 3.6 m.
Explanation:
Given that,
Potential of first sphere = 450 V
Radial distance = 7.2 m
If the potential of sphere =150 V
We need to calculate the radius
Using formula for potential
For 450 V
....(I)
For 150 V
....(II)
Divided equation (I) by equation (II)
Hence, The radius of the sphere is 3.6 m.
