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Anna71 [15]
3 years ago
6

One fine summer day a group of students was jumping from a railroad bridge into the river below. They stepped off the bridge wit

h an acceleration (due to gravity) of 9.8 m/s2 and they hit the water 1.5 s later. How high (in meters) was the bridge? Only enter the number, not the units.
Physics
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

11 m

Explanation:

The following data were obtained from the question:

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 1.5 s

Height (h) =..?

The height of the bridge can be obtained by using the following formula:

h =½gt²

h = ½ × 9.8 × 1.5²

= 4.9 × 2.25

= 11.025 ≈ 11 m

Thus, the height of the bridge is approximately 11 m

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Answer:

5773.50269 Hz

23 A

Explanation:

L = Inductance = 6 mH

C = Capacitance = 5 μF

R = Resistance = 3 Ω

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Resonant angular frequency is given by

\omega=\dfrac{1}{\sqrt{LC}}\\\Rightarrow \omega=\dfrac{1}{\sqrt{6\times 10^{-3}\times 5\times 10^{-6}}}\\\Rightarrow \omega=5773.50269\ Hz

The resonant angular frequency is 5773.50269 Hz

Current is given by

I=\dfrac{\epsilon}{R}\\\Rightarrow I=\dfrac{69}{3}\\\Rightarrow I=23\ A

The current amplitude at the resonant angular frequency is 23 A

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an athlete whirls an 8.71 kg hammer tied to the end of a 1.5 m chain in a simple horizontal circle where you should ignore any v
-BARSIC- [3]

Answer:

T = 692.42 N

Explanation:

Given that,

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Length of the chain to which an athlete whirls the hammer, r = 1.5 m

The angular sped of the hammer, \omega=1.16\ rev/s=7.28\ rad/s

We need to find the tension in the chain. The tension acting in the chain is balanced by the required centripetal force. It is given by the formula as follows :

F=m\omega^2r\\\\=8.71\times (7.28)^2\times 1.5\\\\=692.42\ N

So, the tension in the chain is 692.42 N.

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3 years ago
If we use 1 millimeter to represent 1 light-year, how large in diameter is the Milky Way Galaxy?
storchak [24]

Answer:

d.100 meters

Explanation:

The diameter of the Milky Way Galaxy is approximately 100,000 light years.

Here we are using 1 millimiter (1 mm) to represent 1 light-year (1 ly). So, we can set the following proportion:

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