Explanation:
There are five equations of motion:
v = at + v₀
Δx = v₀ t + ½ at²
Δx = ½ (v + v₀)t
v² = v₀² + 2aΔx
Δx = vt − ½ at²
Δx is the displacement
v₀ is the initial velocity
v is the final velocity
a is the acceleration
t is time
Answer:
distance = 6.1022 x10^16[m]
Explanation:
To solve this problem we must use the formula of the average speed which relates distance to time, so we have
v = distance / time
where:
v = velocity = 3 x 10^8 [m/s]
distance = x [meters]
time = 6.45 [light years]
Now we have to convert from light-years to seconds in order to get the distance in meters.
![t = 6.45 [light-years]*365[\frac{days}{1light-year}]*24[\frac{hr}{1day}] *60[\frac{min}{1hr}]*60[\frac{seg}{1min} ] =203407200 [s]](https://tex.z-dn.net/?f=t%20%3D%206.45%20%5Blight-years%5D%2A365%5B%5Cfrac%7Bdays%7D%7B1light-year%7D%5D%2A24%5B%5Cfrac%7Bhr%7D%7B1day%7D%5D%20%2A60%5B%5Cfrac%7Bmin%7D%7B1hr%7D%5D%2A60%5B%5Cfrac%7Bseg%7D%7B1min%7D%20%5D%20%3D203407200%20%5Bs%5D)
Now using the formula:
distance = v * time
distance = (3*10^8)*203407200
distance = 6.1022 x10^16[m]
Answer: If a star's radial velocity is -50 km/s, the frequency of its light would appear to be higher than its true frequency. We usually say that the star's wavelength is blue shifted.
Explanation:
Radial velocity is defined as the velocity of how an object is seen by the axis of a circle.
Then, if the radial velocity is -50km/s, this means that the radius is decreasing, and then that the star is coming towards the viewer.
as the star is coming towards the viewer, we will see a shorter wavelength, which implies that the frequency would appear to be bigger as it really is.
and this is called a blue shift, because the blue light is the visible light with the biggest frequency, while the red light is the visible light with the smallest frequency, then we have:
If a star's radial velocity is -50 km/s, the frequency of its light would appear to be higher than its true frequency. We usually say that the star's wavelength is blue shifted.
when no net external torque acts on the system then the angular momentum of a system becomes constant. In mechanics and physics, a torque is the spinning counterpart to a force.
The rotating counterpart of linear momentum in physics is called angular momentum. Given that the total angular momentum is conserved, or remains constant in a closed system, it is an important physical quantity. Angular momentum is conserved in both its magnitude and direction. Bicycles, motorcycles, frisbees, rifled bullets, and gyroscopes are all useful objects thanks to the conservation of angular momentum.
The torque is the ratio of the force's magnitude to the angle at which its line of action is perpendicular to the axis of rotation. The cross product of the position vector and the torque, a three-dimensional pseudovector, yields the torque for point particles.
learn more about torque here
brainly.com/question/28220969
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Answer:
Explanation:
given,
scattering angle of alpha particle = 25.0° above its initial direction of motion
oxygen nucleus recoils at = 50.0° below this initial direction.
final speed of the oxygen = 2.08×10⁵ m/s
mass of alpha particle = 4.0 u
mass o oxygen nucleus = 16 u
momentum conservation along x- axis
....(1)
Along y-direction
putting value in equation (1)
