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bekas [8.4K]
3 years ago
10

an automobile has a tire pressure of 325 kpa when the temperature is 10°C of the temperature rises to 50°C what is the new press

ure
Physics
1 answer:
Finger [1]3 years ago
8 0
Old temperature = 283 K.
New temp = 323 K.

(323/283) x (325 kPa) = 371 kPa.
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What is the frequency of a microwave with a wavelength of 3.52 mm?
AlekseyPX

As per the question the wavelength of the microwave is given as 3.52 mm.

we are asked to calculate the frequency of the wave.

we know that microwave is a electromagnetic wave.

As per Clark Maxwell's electromagnetic theory ,every electromagnetic wave moves with a velocity equal to the velocity of light in vacuum and that is equal to 3×10^8 m/s.

From the equation of the wave,we know that velocity of wave is the product of frequency and wavelength.

Mathematically   wave velocity v=f*\lambda   where f is the frequency of the wave and \lambda is the wavelength.

As per the question \lambda=3.52 mm

                                               = 3.52*10^{-3} m

                       Here  v=c=3*10^{8} m/s

Hence frequency of the wave f=\frac{v}{\lambda}

                                                       =\frac{3*10^{8} }{3.52*10^{-3} } s^{-1}

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PLS HELP!!
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Answer:

B

Explanation:

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padilas [110]

Answer:

I = 1.21x10^-5 A

Explanation:

You are missing the first part of the problem. This is an example, but it will give you the idea of how to solve yours with your data.

The first part is like this:

<em>A      4.0 cm  diameter parallel plate capacitor has a  0.44 m  m    gap. What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000 V/s?</em>

Now with this, we can solve the problem.

In order to do this, we need to use the following expression:

q = CV (1)

Where:

C: Capacitance of a parellel capacitor (in Faraday)

q: charge of plate or capacitor (In coulombs)

V: voltage in Volts.

However, we need is the current, and we have data of potential difference, so, all we have to do is divide the expression between time so:

q/t = CV/t

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\huge{\underline{\underline{\red{Answer}}}}

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Answer:

It will be easier to break the meter rule with the long side against my knee.

Explanation:

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