Charge appeared on the plates of a 6.0 μf capacitor when it is charged to 40V is 240μC.
Capacitance of the capacitor is determined by the area of the plate of Capacitor and distance between the plates of capacitor.
Capacitor is dependent on the area of the plates, distance between the plates and medium present between the plates.
It is not dependent of the charge and voltage across the capacitor.
We know that Q = CV, where Q is the charge on capacitor, C is the Capacitance and V is the voltage applied across the capacitor.
Q = 6 × 10⁻⁶ × 40
Q = 240× 10⁻⁶ C
Q = 240 μC
Hence the charge on the plates of the capacitor is 240 μC.
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Answer:
measurement of force amplification
Answer:
8977.7 kg/m^3
Explanation:
Volume of water displaced = 55 cm^3 = 55 x 10^-6 m^3
Reading of balance when block is immersed in water = 4.3 N
According to the Archimedes principle, when a body is immersed n a liquid partly or wholly, then there is a loss in the weight of body which is called upthrust or buoyant force. this buoyant force is equal to the weight of liquid displaced by the body.
Buoyant force = weight of the water displaced by the block
Buoyant force = Volume of water displaced x density of water x g
= 55 x 10^-6 x 1000 x .8 = 0.539 N
True weight of the body = Weight of body in water + buoyant force
m g = 4.3 + 0.539 = 4.839
m = 0.4937 kg
Density of block = mass of block / volume of block
=
Density of block = 8977.7 kg/m^3
The answer is the troposphere you breathe in the air
In projectile motion we know that range of projectile is given as
also the maximum height is given as
so here we can see that maximum height and range on earth will inversely depends on gravity
now if we compare this height and range on earth and moon
similarly for height we have
so both will increase by factor of 7.26