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Ahat [919]
4 years ago
15

What mass of iron is found in 280 g of 2 ppm solution?

Chemistry
1 answer:
Nataly_w [17]4 years ago
6 0

<u>Answer:</u> The mass of iron found in the solution is 0.56 mg

<u>Explanation:</u>

ppm is the amount of solute (in milligrams) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6

Both the masses are in grams.

We are given:

Concentration of iron = 2 ppm

Mass of solution = 280 g

Putting values in above equation, we get:

2=\frac{\text{Mass of iron}}{280g}\times 10^6\\\\\text{Mass of iron}=\frac{2\times 280}{10^6}=0.00056g=0.56mg

<u>Conversion factor used:</u>  1 g = 1000 mg

Hence, the mass of iron found in the solution is 0.56 mg

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Novosadov [1.4K]

Answer:

\boxed {\boxed {\sf 0.495 \ mol}}

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We are given a number of particles and asked to convert to moles.

<h3>1. Convert Particles to Moles </h3>

1 mole of any substance contains the same number of particles (atoms, molecules, formula units) : 6.022 *10²³ or Avogadro's Number. For this question, the particles are not specified.

So, we know that 1 mole of this substance contains 6.022 *10²³ particles. Let's set up a ratio.

\frac { 1 \ mol }{6.022*10^{23 } \ particles}}

We are converting 2.98*10²³ particles to moles, so we multiply the ratio by that value.

2.98*10^{23} \ particles *\frac { 1 \ mol }{6.022*10^{23 } \ particles}}

The units of particles cancel.

2.98*10^{23}  *\frac { 1 \ mol }{6.022*10^{23 } }}

\frac { 2.98*10^{23}}{6.022*10^{23 } }}  \ mol

0.4948522086 \ mol

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For the number we found, 3 sig figs is the thousandth place.

The 8 in the ten-thousandth place (0.4948522086) tells us to round the 4 up to a 5 in the thousandth place.

0.495 \ mol

2.98*10²³ particles are equal to approximately <u>0.495 moles.</u>

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