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Viefleur [7K]
3 years ago
12

A plant box falls from the windowsill 25.0 m above the sidewalk and hits the cement 3.0 s later. What is the box's velocity when

it hits the ground?
24 m/s
22 m/s
120 m/s
Physics
1 answer:
mamaluj [8]3 years ago
8 0

Answer:

22m/s

Explanation:

To find the velocity we employ the equation of free fall: v²=u²+2gh

where u is initial velocity, g is acceleration due to gravity h is the height, v is the velocity the moment it hits the ground, taking the direction towards gravity as positive.

Substituting for the values in the question we get:

v²=2×9.8m/s²×25m

v²=490m²/s²

v=22.14m/s which can be approximated to 22m/s

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What happens to the sum of the ball's kinetic energy and potential energy as the ball rolls from point A to point E? Assume ther
sesenic [268]

Answer:

C. The sum remains the same.

Explanation:

The sum of the kinetic and potential energy remains the same as the all rolls from point A to E.

We know this based on the law of conservation of energy that is in play within the system.

The law of conservation of energy states that "energy is neither created nor destroyed within a system but transformed from one form to another".

  • At the top of the potential energy is maximum
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7 0
3 years ago
A spring (k = 200 N/m) is fixed at the top of a frictionless plane inclined at angle θ = 33 °. A 1.2 kg block is projected up th
Serga [27]

Answer:

Explanation:

Initial kinetic energy = 29 J

work done against gravity = mgsin33 x d  , m is mass of the block

= 1.2 x 9.8 sin 33 x .9

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b )

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= 21.76 J

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