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Dimas [21]
3 years ago
9

An oxidation number

Chemistry
1 answer:
melamori03 [73]3 years ago
5 0
D. is the same in each compound that an element forms
Hope it helps:)
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Magnesium reacts steadily with hydrochloric acid
balu736 [363]

Magnesium + Hydrocloric acid -> Magnesium chloride + hydrogen

You can observe a single displacement reaction

"Describe to show that the has formed is hydrogen"

I don't know what you mean. I can show the chemical equation though.

Mg(s) + 2 HCl(aq) --> MgCl 2(aq) + H 2(g)

3 0
3 years ago
Besides the concentration of the acid and its conjugate base, what else does one need to calculate the ph of a weak acid
Marta_Voda [28]
K_{a}, the acid disassociation constant. 
3 0
3 years ago
How many grams of the excess reactant remain assuming the reaction goes to completion and that you start with 15.5g of na2s and
tangare [24]
The reaction between Na2S and CuSO4 will give us the balanced chemical reaction of,
                                     Na2S + CUSO4 --> Na2SO4 + CuS
This means that for every 78g of Na2S, there needs to be 159.6 g of CuSO4. The ratio is equal to 0.4887 of Na2S: 1 of CuSO4. Thus, for every 12.1g of CuSO4, we need only 5.91 g of Na2S. Thus, there is an excess of 9.58 g of Na2S. The answer is letter C. 
8 0
3 years ago
Read 2 more answers
If kerosene has a specific gravity of 0.820, what force will be exerted on the circular bottom of a cylindrical kerosene tank th
Svet_ta [14]

Answer:

F = 774146.534\,N

Explanation:

The pressure at the bottom of the tank is:

P_{bottom} = (0.820)\cdot (1000\,\frac{kg}{m^{3}})\cdot (9.807\,\frac{m}{s^{2}})\cdot (30\,ft)\cdot (\frac{0.305\,m}{1\,ft} )

P_{bottom} = 73581.921\,Pa

The force exerted on the circular bottom is:

F=(73581.921\,Pa)\cdot (\frac{\pi}{4} )\cdot [(12\,ft)\cdot (\frac{0.305\,m}{1\,ft} )]^{2}

F = 774146.534\,N

4 0
3 years ago
Stronger acids are those that —
Harlamova29_29 [7]
F. hold on to their protons more strongly
7 0
3 years ago
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