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jok3333 [9.3K]
3 years ago
13

If kerosene has a specific gravity of 0.820, what force will be exerted on the circular bottom of a cylindrical kerosene tank th

at has a diameter of 12-ft and a height of 30 ft?
Chemistry
1 answer:
Svet_ta [14]3 years ago
4 0

Answer:

F = 774146.534\,N

Explanation:

The pressure at the bottom of the tank is:

P_{bottom} = (0.820)\cdot (1000\,\frac{kg}{m^{3}})\cdot (9.807\,\frac{m}{s^{2}})\cdot (30\,ft)\cdot (\frac{0.305\,m}{1\,ft} )

P_{bottom} = 73581.921\,Pa

The force exerted on the circular bottom is:

F=(73581.921\,Pa)\cdot (\frac{\pi}{4} )\cdot [(12\,ft)\cdot (\frac{0.305\,m}{1\,ft} )]^{2}

F = 774146.534\,N

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A sample compound contains 9.11 g Ni and 5.89g F. What is the empirical formula of this compound?
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The empirical formula of the compound is C. NiF₂.

<em>Step 1</em>. Calculate the <em>moles of each element</em>

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Ni to F.

Moles of Ni = 9.11 g Ni × (1 mol Ni /(58.69 g Ni) = 0.1552 mol Ni

Moles of F = 5.89 g F × (1 mol F/19.00 g F) = 0.3100 mol F

<em>Step 2</em>. Calculate the <em>molar ratio</em> of the elements

Divide each number by the smallest number of moles

Ni:F = 0.1552:0.3100 = 1:1.997 ≈ 1:2

<em>Step 3</em>: Write the <em>empirical formula</em>

EF = NiF₂

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A 50 W engine generates 50 J of energy. How long did it run for?
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The engine ran for 10 second
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If your lawn is 21.0 ft wide and 20.0 ft long, and each square foot of lawn accumulates 1350 new snow flakes every minute. How m
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<span>First we can calculate the area of the rectangular lawn using the formula:
Area = Width x Length = 21 ft x 20 ft = 420 square feet
       
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In one hour (or 60 minutes) we get a total of:
   
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7 0
3 years ago
A solid, pure substance containing just carbon and hydrogen is found to contain 35.8g of carbon and 3.72 g of hydrogen. how many
Igoryamba

Answer:

            4.36 g of Carbon

Solution:

Step 1: Calculate the %age of Carbon in given Solid as;

                        Mass of Carbon  =  35.8 g

                        Mass of Hydrogen  =  3.72

                        Total Mass  =  35.8 g + 3.72  =  39.52 g

                        %age of Carbon  =  (35.8 g ÷ 39.52 g) × 100

                        %age of carbon  =  90.58 %

Step 2: Calculate grams of Carbon in 4.82 g of given solid as;

                        Mass of Carbon  =  4.82 g × (90.58 ÷ 100)

                        Mass of Carbon  =  4.36 g

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