What is the only thing that can pull a beam of light towards itself ?
2 answers:
Mirror trust me hjhgguujgffr
Answer:
<h2>
<em>The </em><em>only </em><em>thing</em><em> </em><em>that</em><em> </em><em>can</em><em> </em><em>pull</em><em> </em><em>a </em><em>beam </em><em>of</em><em> light</em><em> </em><em>towards</em><em> </em><em>it</em><em> </em><em>self</em><em> </em><em>is </em><em>a </em><em>black </em><em>hole.</em></h2>
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a. potential energy.
hope this helps, please mark brainliest :).
VOLT
USE OHMS LAW V=IR
GREAT WORK SO FAR KEEP IT UP TIGER
Answer:
Explanation:
the hitting should be in the almost top so the more faster and strong u hit more the ball more at top will go and more far will go
Answer:![T_L=-154.2^{\circ}](https://tex.z-dn.net/?f=T_L%3D-154.2%5E%7B%5Ccirc%7D)
Explanation:
Given
COP= 60 % of carnot heat pump
![COP=\frac{60}{100}\times \frac{T_H}{T_H-T_L}](https://tex.z-dn.net/?f=COP%3D%5Cfrac%7B60%7D%7B100%7D%5Ctimes%20%5Cfrac%7BT_H%7D%7BT_H-T_L%7D)
For heat added directly to be as efficient as via heat pump
![Q_s=W](https://tex.z-dn.net/?f=Q_s%3DW)
![COP=\frac{Q_s}{W}=\frac{60}{100}\times \frac{T_H}{T_H-T_L}](https://tex.z-dn.net/?f=COP%3D%5Cfrac%7BQ_s%7D%7BW%7D%3D%5Cfrac%7B60%7D%7B100%7D%5Ctimes%20%5Cfrac%7BT_H%7D%7BT_H-T_L%7D)
![1=\frac{60}{100}\times \frac{T_H}{T_H-T_L}](https://tex.z-dn.net/?f=1%3D%5Cfrac%7B60%7D%7B100%7D%5Ctimes%20%5Cfrac%7BT_H%7D%7BT_H-T_L%7D)
![1=\frac{60}{100}\times \frac{24+273}{24+273-T_L}](https://tex.z-dn.net/?f=1%3D%5Cfrac%7B60%7D%7B100%7D%5Ctimes%20%5Cfrac%7B24%2B273%7D%7B24%2B273-T_L%7D)
![T_L=118.8 K](https://tex.z-dn.net/?f=T_L%3D118.8%20K)
![T_L=-154.2^{\circ}](https://tex.z-dn.net/?f=T_L%3D-154.2%5E%7B%5Ccirc%7D)
We first calculate the friction on the sled using:
F = ma
a = 20 / 22
a = 0.91 m/s²
Now we use the formula:
2as = v² - u²
v = √(2as + u²)
v = √[2(0.91)(5.2) + 0]
v = 3.08 m/s