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erastova [34]
3 years ago
11

One example of a physical change is

Physics
1 answer:
ycow [4]3 years ago
7 0

Answer:

Mixing a milkshake

Explanation:

Becuse it’s physics becuse your using muscle and moving it and changing it by force.

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A 98-kg fullback, running at 5.0 m/s, attempts to dive directly across the goal line for a touchdown. Just as he reaches the lin
Troyanec [42]

Answer:

(a) Explained below

(b) v_f=0.35\ m/s

(c) Yes

Explanation:

<u>Law Of Conservation Of Linear Momentum</u>

The total linear momentum of a system of particles or objects is conserved unless an external force is acting on the system. The formula for the momentum of a body with mass m and velocity v is P=mv. If there is a system of bodies, then the total linear momentum is the sum of the individual momentums

P=m_1v_1+m_2v_2+...+m_nv_n

When objects collide and join together, the only final mass is the sum of all masses, all traveling at the same speed.

Our m_1=98\ kg fullback runs at v_1=5\ m/s. Two two 68-kg linebackers attempt to stop him, one at -2.0 m/s and the other at -4.0 m/s. The negative value is because the run against the positive direction, taken in the direction of the fullback.

(a) Before the event, there is a total linear momentum, computed as the sum of the momentums of each player as shown

p_1=m_1v_1=(98)(5)=490 Kg\ m/s

p_2=m_2v_2=(68)(-4)=-272 kg\ m/s

p_3=m_3v_3=(68)(-2)=-136 kg\ m/s

p_t=p_1+p_2+p_3=390-272-136=82\ kg\ m/s

After the collision, all the players keep joined in one single mass of.

m_t=98+68+68=234\ kg

They will move at a speed which will be computed below

(b) The final momentum of the system is

p_f=m_tv_f=82\ kg\ m/s

Since the linear momentum is conserved, the final speed v_f is common to all of the players. Let's solve to find it

\displaystyle v_f=\frac{p_f}{m_t}

\displaystyle v_f=\frac{82}{234}

v_f=0.35\ m/s

(c) Since the final speed of the players is positive, it means the touchdown was actually scored, the fullback moved forward across the goal line, the positive reference.

5 0
3 years ago
How long does it take an object to travel 375 m at a rate of 25 m/s?
Leni [432]

Answer:

15s

Explanation:

Given parameters:

Distance traveled  = 375m

Speed = 25m/s

Unknown:

Time taken = ?

Solution:

To solve this problem, we make time the subject of the speed equation.

    Speed  = \frac{distance}{time}  

  Time  = \frac{distance}{speed}  

 Now insert the parameters and solve;

  Time  = \frac{375}{25}   = 15s

3 0
3 years ago
What is an astronomer? Answer in the simpliest way please.
Sphinxa [80]
They would be an expert in astronomy
astronomy:the branch of science that deals with celestial objects
8 0
3 years ago
A golf club rotates 215 degrees and has a length (radius) equal to 29 inches. The time it took to swing the club was 0.8 seconds
vichka [17]

Answer:

The average linear velocity (inches/second) of the golf club is 136.01 inches/second

Explanation:

Given;

length of the club, L = 29 inches

rotation angle, θ = 215⁰

time of motion, t = 0.8 s

The angular speed of the club is calculated as follows;

\omega = (\frac{\theta}{360} \times 2\pi, \ rad) \times \frac{1}{t} \\\\\omega =  (\frac{215}{360} \times 2\pi, \ rad) \times \frac{1}{0.8 \ s} \\\\\omega = 4.69 \ rad/s

The average linear velocity (inches/second) of the golf club is calculated as;

v = ωr

v = 4.69 rad/s  x  29 inches

v = 136.01 inches/second

Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second

8 0
2 years ago
How do i solve?<br><br>a = bc<br>(b)​
stira [4]
I don’t even know I’m so dumb.
7 0
3 years ago
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