Answer:

Explanation:
- We have to make a hollow sphere of inner radius
and outer radius
.
Then the mass of the material required to make such a sphere would be calculated as:
Total volume of the spherical shell:

And the volume of the hollow space in the sphere:

Therefore the net volume of material required to make the sphere:


- Now let the density of the of the material be
.
<u>Then the mass of the material used is:</u>


Answer:
twice
Explanation:
From magnification = height of image / height of object
Distance of image/ distance of object = magnification
If the distance and height of the object represents the initial light distance and the exposed surface respectively.
And similarly the distance and height of the image represents the final light distance and the exposed surface respectively.
Hence the new image exposure would be twice as large.
If we use the formula our point of investigation is Height of image,
H2= D2/D1× H1
H2 = 2D2/D1 × H1
H2 = 2H1
The force which has the greatest effect on causing this object to slow while it remains in contact with the ramp is: B. a frictional force.
<h3>What is a force?</h3>
A force can be defined as a push or pull of an object or physical body, which typically results in a change of motion (acceleration), especially due to the interaction of the object with another.
<h3>The types of force.</h3>
In Science, there are different types of force and these include the following:
<h3>What is a
frictional force?</h3>
Friction force can be defined as a type of force that resists and slows the relative motion of two physical objects when there surfaces come in contact. This ultimately implies that, a frictional force prevents two surfaces from easily sliding over or slipping across one another.
In this context, we can infer and logically deduce that the force which has the greatest effect on causing this object to slow while it remains in contact with the ramp is a frictional force.
Read more on frictional force here: brainly.com/question/25253774
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Complete Question:
Brandon pushes an object on a ramp as shown in the diagram.
While Brandon pushes the object and it remains in contact the ramp, which force has the greatest effect on causing it to slow?
A. the applied force
B. a frictional force
C. the force due to gravity
D. a force of air resistance
Answer:
a ) 11.1 *10^3 m/s = 39.96 Km/h
b) T_{o2} =1.58*10^5 K
Explanation:
a)
= 11.1 km/s =11.1 *10^3 m/s = 39.96 Km/h
b)
M_O2 = 32.00 g/mol =32.0*10^{-3} kg/mol
gas constant R = 8.31 j/mol.K

So, 
multiply each side by M_{o2}, so we have

solving for temperature T_{o2}

In the question given,

T_{o2} =1.58*10^5 K
Answer:
The power expended by the car during the acceleration is 116.38KW
Explanation:
Power is a term that defines the rate at which energy is expended whenever work is done.
Power can be given as Force X velocity.
Force can be found using the formula:
F = mass X acceleration.
In this case,
F = 1100kg X 4.6m/s2
F = 5060 N
The final velocity, v of the car can be obtained from this formula:
v = u+ at
U = initial velocity = 0 (since the car started from rest)
a = acceleration = 4.6m/s2
t = time = 5 seconds
v = 0 + 4.6 X 5 = 23 m/s
Therefore, the power expended is 5060N X 23m/s=116,380W
The power expended by the car during the acceleration is 116.38KW