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tino4ka555 [31]
3 years ago
9

A flat disk, a solid sphere, and a hollow sphere each have the same mass m and radius r. The three objects are arranged so that

an axis of rotation passes through the center of each object. The rotation axis is perpendicular to the plane of the flat disk. Which of the three objects has the largest moment of inertia?a. The solid sphere and hollow sphere are tied for largest moment of inertia.
b. The hollow sphere has the largest moment of inertia.
c. The solid sphere has the largest moment of inertia.
d. The flat disk has the largest moment of inertia.
e. The flat disk and hollow sphere are tied for largest moment of inertia.
Physics
1 answer:
chubhunter [2.5K]3 years ago
4 0

Answer:

Explanation:The rotational inertia of any object depends directly on the distance the mass is from the axis of a rotating object

Having more mass at the sides will increase the rotational inertia of the object that is why a Hollow sphere having same M and R as the solid one has more rotational inertia as it has more mass at the sides.

The  sphere have some mass at the center but most of its mass is closer to its radius and thus have more inertia than flat Disk.

The same relation exist between a flat disk and hollow sphere. The hollow sphere have some mass at the center but most of its mass is closer to its radius and thus have more inertia.

The rotational of the objects can be calculated by these equations

FlatDisk=\frac{1}{4} MR^2\\Sphere=\frac{2}{5} MR^2\\HollowSphere=\frac{2}{3} MR^2\\

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Norma-Jean [14]

Answer:

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Explanation:

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You place a cup of 210 degrees F coffee on a table in a room that is 68 degrees F, and 10 minutes later, it is 200 degrees F. Ap
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The answer is 35 minutes

The Newton's law of cooling is:
T(x) = Ta + (To - Ta)e⁻ⁿˣ

T(x) - the temperature of the coffee at time x
Ta - the ambient temperature
To - the initial temperature
n - constant

step 1. Calculate constant k:

We have:
T(x) = 200°F
x = 10 min
Ta = 68°F
To = 210°F
n = ?

T(x) = Ta + (To - Ta)e⁻ⁿˣ
200 = 68 + (210 - 68)e⁻ⁿ*¹⁰
200 = 68 + 142 * e⁻¹⁰ⁿ
200 - 68 = 142 * e⁻¹⁰ⁿ
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e⁻¹⁰ⁿ = 132/142
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Logarithm both sides with natural logarithm:
ln(e⁻¹⁰ⁿ) = ln(0.93)
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-10n * 1 = - 0.07
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Step 2. Calculate time x when T(x) = 180°F:
We have:
T(x) = 180°F
x = ?
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To = 210°F
n = 0.007

T(x) = Ta + (To - Ta)e⁻ⁿˣ
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e⁻⁰.⁰⁰⁷*ˣ = 112/142
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Logarithm both sides with natural logarithm:
ln(e⁻⁰.⁰⁰⁷*ˣ) = ln(0.79)
-0.007x * ln(e) = -0.24
-0.007x * 1 = -0.24
-0.007x = -0.24
x = -0.24 / -0.007
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