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Bad White [126]
3 years ago
9

The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s

= 5 sin(πt) + 5 cos(πt), where t is measured in seconds. (Round your answers to two decimal places.) (a) Find the average velocity during each time period. g
Physics
1 answer:
Veseljchak [2.6K]3 years ago
4 0

Answer:

v_{avg} = 0

Explanation:

The object is moving to and fro about its mean position

and the equation for its displacement is given as

s = 5 sin(\pi t) + 5 cos(\pi t)

now in one complete time period we know that the the object will complete its one oscillation

So the change in the position of the object in one complete time period will be ZERO

so here we can say that

v_{avg} = \frac{displacement}{time}

since change in position is zero

so displacement = 0

v_{avg} = 0

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______________ are chemicals in the body affecting how you feel.
7nadin3 [17]

Answer:

emotions

Explanation:

emotions are how you feel and can happen any time

Hope it helps <333

3 0
2 years ago
Read 2 more answers
A particular 12 V car battery can send a total charge of 110 A·h (ampere-hours) through a circuit, from one terminal to the othe
DiKsa [7]
<h2>Answer:</h2>

(a) 3.96 x 10⁵C

(b) 4.752 x 10⁶ J

<h2>Explanation:</h2>

(a) The given charge (Q) is 110 A·h (ampere hour)

Converting this to A·s (ampere second) gives the number of coulombs the charge represents. This is done as follows;

=> Q = 110A·h

=> Q = 110 x 1A x 1h          [1 hour = 3600 seconds]

=> Q = 110 x A x 3600s

=> Q = 396000A·s

=> Q = 3.96 x 10⁵A·s = 3.96 x 10⁵C

Therefore, the number of coulombs of charge is 3.96 x 10⁵C

(b) The energy (E) involved in the process is given by;

E = Q x V           -----------------(i)

Where;

Q = magnitude of the charge = 3.96 x 10⁵C

V = electric potential = 12V

Substitute these values into equation (i) as follows;

E = 3.96 x 10⁵ x 12

E = 47.52 x 10⁵ J

E = 4.752 x 10⁶ J

Therefore, the amount of energy involved is 4.752 x 10⁶ J

8 0
3 years ago
If you know this please help
Ainat [17]

Answer:

b.

Explanation:

It's b I sis thebksqjwnsx0qkqnsnd991isnd

3 0
3 years ago
Read 2 more answers
An object falls from a high building and hits the ground in 8.0 seconds. Ignoring air resistance, what is the distance that it f
d1i1m1o1n [39]

Answer:

310 meters

Explanation:

Given:

v₀ = 0 m/s

t = 8.0 s

a = -9.8 m/s²

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (8.0 s) + ½ (-9.8 m/s²) (8.0 s)²

Δy = -313.6

Rounded to two significant figures, the object fell 310 meters.

4 0
3 years ago
A 0.40-kg block is attached to the end of a horizontal ideal spring and rests on a frictionless surface. The block is pulled so
lubasha [3.4K]

Answer:

160N/m

Explanation:

According to Hooke's law which states that the extension of an elastic material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically,

F = ke where

F is the applied force

k is the spring constant

e is the extension

From the formula k = F/e

Since the body accelerates when the block is released, F = ma according to Newton's second law of motion.

The spring constant k = ma/e where

m is the mass of the block = 0.4kg

a is the acceleration = 8.0m/s²

e is the extension of the spring = 2.0cm = 0.02m

K = 0.4×8/0.02

K = 3.2/0.02

K = 160N/m

The spring constant of the spring is therefore 160N/m

4 0
3 years ago
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