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Bad White [126]
3 years ago
9

The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s

= 5 sin(πt) + 5 cos(πt), where t is measured in seconds. (Round your answers to two decimal places.) (a) Find the average velocity during each time period. g
Physics
1 answer:
Veseljchak [2.6K]3 years ago
4 0

Answer:

v_{avg} = 0

Explanation:

The object is moving to and fro about its mean position

and the equation for its displacement is given as

s = 5 sin(\pi t) + 5 cos(\pi t)

now in one complete time period we know that the the object will complete its one oscillation

So the change in the position of the object in one complete time period will be ZERO

so here we can say that

v_{avg} = \frac{displacement}{time}

since change in position is zero

so displacement = 0

v_{avg} = 0

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Answer:

4.29×10⁵ C

Explanation:

From the question,

The energy stored in the battery = Kinetic energy of the car+ Energy needed to make the car climbed the hill+Energy required to exert a force.

E = 1/2mv²+mgh+Fd.................... Equation 1

Where E = Energy stored in the battery, m = mass of the car, v = velocity of the car, h = height of the hill, F = force exerted on the car, d = distance traveled by the car.

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d = vt.................... Equation 2

Where v = velocity, t = time.

Substitute equation 2 into equation 1

E = 1/2mv²+mgh+F(vt)................... Equation 3

Given: m = 770 kg, v = 26 m/s, h = 2.15×10² m = 215 m, F = 5.3×10² N = 530 N, t = 1 hour = 3600 s, g = 9.8 m/s²

Substitute into equation 1

E = 1/2(770)(26²)+(770)(9.8)(215)+(530)(26)(3600)

E = 260260+1622390+49608000

E = 51490650 J

Using,

E = qV................. Equation 4

Where q = charge of the battery, V = Voltage.

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q = E/V............... Equation 5

Given: E = 51490650 J, V = 120 V

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