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3 years ago

What time period did fish develop

Physics

1 answer:

marysya [2.9K]3 years ago

5 0

Answer:

They developed during the Cambrian time period, which was around 530 million years ago.

Explanation:

Hope this Helps!

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25. Explain why the speed of sound is faster in solids than in gases. Include two other factors Chapter 17 says the speed of sou

aksik [14]

In solids, particles or atom are very closely arranged compared to gasses. When these particles are arranged in such proximity, vibrations from sound are very easily transmitted from one particle to another in the solid. Hence, the sound vibrations can travel through the solid medium more quickly than through a gas medium.
Speed of sound also depends on its frequency and the wavelength.

7 0

2 years ago

A diatomic gas at 333 k has an internal energy of 2930 j. how many moles are present (unit=mol)

tensa zangetsu [6.8K]

Answer:

0.42

Explanation:

4 0

2 years ago

One string of a certain musical instrument is 70.0 cm long and has a mass of 8.79 g . It is being played in a room where the spe

Svetach [21]

To solve this problem we will apply the concepts of linear mass density, and the expression of the wavelength with which we can find the frequency of the string. With these values it will be possible to find the voltage value. Later we will apply concepts related to harmonic waves in order to find the fundamental frequency.

The linear mass density is given as,

$\mu = \frac{m}{l}$

$\mu = \frac{8.79*10^{-3}}{70*10^{-2}}$

$\mu = 0.01255kg/m$

The expression for the wavelength of the standing wave for the second overtone is

$\lambda = \frac{2}{3} l$

Replacing we have

$\lambda = \frac{2}{3} (70*10^{-2})$

$\lambda = 0.466m$

The frequency of the sound wave is

$f_s = \frac{v}{\lambda_s}$

$f_s = \frac{344}{0.768}$

$f_s = 448Hz$

Now the velocity of the wave would be

$v = f_s \lambda$

$v = (448)(0.466)$

$v = 208.768m/s$

The expression that relates the velocity of the wave, tension on the string and linear mass density is

$v = \sqrt{\frac{T}{\mu}}$

$v^2 = \frac{T}{\mu}$

$T= \mu v^2$

$T = (0.01255kg/m)(208.768m/s)^2$

$T = 547N$

The tension in the string is 547N

PART B) The relation between the fundamental frequency and the $n^{th}$ harmonic frequency is

$f_n = nf_1$

Overtone is the resonant frequency above the fundamental frequency. The second overtone is the second resonant frequency after the fundamental frequency. Therefore

$n=3$

Then,

$f_3 = 3f_1$

Rearranging to find the fundamental frequency

$f_1 = \frac{f_3}{3}$

$f_1 = \frac{448Hz}{3}$

$f_1 = 149.9Hz$

7 0

2 years ago

How many position coordinates are required to identify the position of a system undergoing one-dimensional motion? What symbol s

gregori [183]

One-dimensional motion can be plotted through the Cartesian plane which has a coordinates of (x,y). These coordinates are the abscissa and ordinates. Since, there are two coordinates, the answer to the second item is two.

The symbol that can be used to identify systems position is (x,y). Since this is one dimensional motion, it is possible that one of the two coordinates becomes zero.

6 0

3 years ago

A rock is dropped from a height of 3,245 m. If we ignore air resistance, how fast will it be travelling after it falls for 3.4 s

Marta_Voda [28]

Answer:

954.4m/s

Explanation:

For a free falling object,it has constant acceleration and a changing velocity.

By using the velocity-time formula, the velocity can be obtained.

The height the rock travelled is the distance.

From,

Velocity (v) = Distance (d) / Time(t)

v = 3245m/3.4s

v = 954.4m/s

That js the answer I got. Hope it's right.

3 0

2 years ago