Answer 10
Explication nose
Answer:
0.5 M
Explanation:
From the question given above, the following data were obtained:
Mass of NaOH = 80 g
Volume of solution = 4 L
Molarity =?
Next, we shall determine the number of mole in 80 g of NaOH. This can be obtained as follow:
Mass of NaOH = 80 g
Molar mass of NaOH = 23 + 16 + 1
= 40 g/mol
Mole of NaOH =?
Mole = mass / molar mass
Mole of NaOH = 80 / 40
Mole of NaOH = 2 moles
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Mole of NaOH = 2 moles
Volume of solution = 4 L
Molarity =?
Molarity = mole / Volume
Molarity = 2/4
Molarity = 0.5 M
Therefore, the molarity of the solution is 0.5 M.
c)distance between two of the numbered lines
Explanation:
On a meter stick, a centimeter is usually the distance between two of the numbered lines. A meter stick is a device for measuring the length of an object.
- A hundred centimeters makes up a meter and this is the number of divisions on a meter stick.
- Each distance between numbered vertical lines is a centimeter apart.
- On a meter stick that is 1m long, there are 100cm.
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Answer:
Approximately
.
Explanation:
The Lyman Series of a hydrogen atom are due to electron transitions from energy levels
to the ground state where
. In this case, the electron responsible for the line started at
and transitioned to
A hydrogen atom contains only one electron. As a result, Bohr Model provides a good estimate of that electron's energy at different levels.
In Bohr's Model, the equation for an electron at energy level
(
(note the negative sign in front of the fraction,)
where
is a constant.
is the atomic number of that atom.
for hydrogen.
is the energy level of that electron.
The electron that produced the
line was initially at the
.
The electron would then transit to energy level
. Its energy would become:
.
The energy change would be equal to
.
That would be the energy of a photon in that
spectrum line. Planck constant
relates the frequency of a photon to its energy:
, where
is the energy of the photon.
is the Planck constant.
is the frequency of that photon.
In this case,
. Hence,
.
Note that
.