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Mama L [17]
3 years ago
6

You have two solutions, both with a concentration of 0.1M. Solution A contains a weak acid with a pKa of 5. The pH of solution A

is 3. Solution B contains a weak acid with a pKa of 9. The pH of solution B is:
Chemistry
1 answer:
viktelen [127]3 years ago
3 0

Answer:guguhi

Explanation:

Guggugj

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What are the controlled variables for water of crystallization experiment?
yarga [219]

Given what we know, we can confirm that as with any experiment, the control variable will be the one that through each trial of the experiment, no matter how many times it is performed, stays constant.

<h3>What is a controlled variable?</h3>
  • A variable that remains constant through an experiment.
  • They are used to compare results to the normal condition.
  • They are also used to isolate the changes to one factor at a time and thus know its exact effects on the outcome.
  • This increases the accuracy of the data and the subsequent conclusion.

Therefore, we can confirm that if a variable stays constant through each phase and trial of an experiment, it is considered to be a controlled variable and is useful in order to increase the accuracy of the conclusion.

To learn more about control variables visit:

brainly.com/question/17555102?referrer=searchResults

7 0
2 years ago
. Which information is NOT included in each square of the periodic table in your text? a. atomic number c. melting point b. chem
azamat
The correct answer is melting point
6 0
3 years ago
If a car is traveling 100 km/h and comes to a stop in 3 minutes,what is acceleration of a passenger who is using vehicle restrai
Rama09 [41]

We are given –

  • Final velocity of car is, v= 0
  • Initial velocity of car is, u= 100 km/hr
  • Time taken, t is = 3 minutes or 180 sec

Here–

\qquad\pink{\bf \longrightarrow  Initial\:  velocity =  100 \:km/hr}

\qquad\sf \longrightarrow  Initial\:  velocity = \dfrac{ 100 \times 1000}{3600} \:m/s

\qquad\pink{ \bf \longrightarrow  Initial\:  velocity = 27.78\: m/s}

Now –

\qquad____________________________

\qquad\purple{\bf \longrightarrow  Acceleration  = \dfrac{Final\: Velocity -Initial  \:Velocity }{Time}}

\qquad\purple{\bf \longrightarrow  Acceleration  = \dfrac{v -u}{t}}

\qquad\sf \longrightarrow  Acceleration = \dfrac{(0- 27.78)}{1800}

\qquad\sf \longrightarrow  Acceleration =\cancel{ \dfrac{- 27.78}{1800}}

\qquad\purple{\bf \longrightarrow  Acceleration = -0.15 \: m/s^2}

\qquad_______________________________

6 0
2 years ago
Why is a chemical equilibrium described as dynamic?
Katen [24]
Because when equilibrium is reached, the reaction is still occurring in both directions, it's just that rate(forward) =rate(reverse) so there is no net change in the concentrations of the reactants or products.
8 0
2 years ago
Read 2 more answers
Calculate the volume in liters of a potassium iodide solution that contains of potassium iodide . Be sure your answer has the co
Anna11 [10]

Answer:

23.8 L

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>

<em />

The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:

150 g × (1 mol/166.00 g) = 0.904 mol

0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:

0.904 mol × (1 L/0.0380 mol) = 23.8 L

6 0
3 years ago
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