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kupik [55]
3 years ago
5

Suppose you have a scientific question you are interested in answering. What would you normally do before you make your hypothes

is? A. Do some background research. B. Conduct a scientific experiment. C. Make predictions about your question. D. Design a procedure for your experiment.
Chemistry
2 answers:
hoa [83]3 years ago
7 0

Answer:

aaaaaaaaaa

Explanation:

STatiana [176]3 years ago
6 0

Answer:

A. Do some background research

There are 5 steps for the scientific method while doing an experiment

Step 1: make a question

Step 2: research that question

Step 3: Hypothesis

Step 4: Test and collect data

Step 5: Conclusion

You might be interested in
A. Clearly draw the Lewis structure for the PBr4- ion. Show your math where
Nataliya [291]

Answer:

   Br

    |

Br-P-Br

    |

   Br

Explanation:

To calculate the valance electrons, look at the periodic table to find the valance electrons for each atom and add them together. P is in column 5A, so it has 5, Br is in column 7A, so it has 7 (multiply by 4 since there are 4 Br atoms to give 28) and there is a 1- charge, so add one more electron. 5+28+1=34, so there are 34 electrons to place. P would be the central atom, so place it in the middle. Place each Br around the P (as shown above) with a a single line connecting it. Each line represents 2 electrons, so 8 total have been place, leaving 26 remaining. Place 6 electrons around each Br (2 on each of the unbonded sides), which leaves 2 electrons remaining. The remaining pair of unbound electrons will be attached to the P between any two Br atoms. Phosphorus doesn't have to follow the octet rule, so it actually ends up with 10 valance electrons.

4 0
2 years ago
Read 2 more answers
2C2H2 + 5O2 → 4CO2 + 2 H2O How many grams of CO2 are required to react with exactly 3.00 mol of O2? 106 g 132 g 165 g 76.8 g
cricket20 [7]

Hey there!:

Given the reaction:

2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

5 moles O2 ------------- 4 moles CO2

3.00 moles O2 ----------  ( moles of CO2 ?? )

moles of CO2 = 3.00 * 4 / 5

moles of CO2 =  12 / 5

moles of CO2 = 2.4 moles

So, molar  mass CO2 = 44.01 g/mol

Therefore:

1 mole CO2 -------------- 44.01 g

2.4 moles CO2 ---------- ( mass of CO2 )

mass of CO2 = 2.4 * 44.01 / 1

mass of CO2 = 106 g

Answer A


Hope that helps!

8 0
3 years ago
How are sea slugs able to make their own food like green algae?
Nadusha1986 [10]

Answer: my answer I’d D! I’m sorry if this did not help you

Explanation: =)

3 0
3 years ago
Read 2 more answers
The AE of a system that releases 12.4 J of heat and does 4.2 J of work on its surroundings It is_______ jA. 16.6 B. 12.4 C. 4.2
andre [41]

ANSWER

EXPLANATION

Given that

The energy released by the system is 12.4J

Work done on the surrounding is 4.2J

Follow the steps below to find the change in energy

In the given data, energy is said to be released to the surroundings

Recall, that exothermic reaction is a type of reaction in which heat is released to the surroundings. Hence, change in enthalpy is negative

Step 1; Write the formula for calculating change in energy

\Delta E\text{ }=\text{ q }+\text{ w}

Since heat is released to the surrounding, then q = -12J

Recall, that work done by the system on the surroundings is always negative

Hence, w = -4.2J

Step 2; Substitute the given data into the formula in step 1

\begin{gathered} \text{  }\Delta E\text{ = q + w} \\ \text{  }\Delta E\text{ }=\text{ -12.4 }+\text{ \lparen-4.2\rparen} \\ \text{  }\Delta E\text{ = -12.4 - 4.2} \\ \text{  }\Delta E\text{ }=\text{ -16.6J} \end{gathered}

Therefore, the change i

3 0
1 year ago
Place the following covalent bonds in order from least to most polar: a. H-Cl b. H-Br c. H-S d. H-C
timofeeve [1]

Answer:


The Order is as follow,

                                     C-H < S-H < H-Br < H-Cl


Explanation:

                      Polarity depends on the electronegativity difference between two atoms, greater the electronegativity difference, greater will be the polarity of bond and vice versa.


Electronegativity Difference between Hydrogen and other given elements are as follow,


1) C-H;

               E.N of Carbon     = 2.55

               E.N of Hydrogen = 2.20

                                           ------------

               Difference              0.35


2) S-H;

               E.N of Sulfur       = 2.58

               E.N of Hydrogen = 2.20

                                           ------------

               Difference               0.38


3) H-Br;

               E.N of Bromine   = 2.96

               E.N of Hydrogen = 2.20

                                          -------------

               Difference              0.76


4) H-Cl;

               E.N of Chlorine   = 3.16

               E.N of Hydrogen = 2.20

                                           -----------

               Difference               0.96


Hence it is proved that the greatest electronegativity difference is found between H and Chlorine in H-Cl, therefore it is highly polar bond and vice versa.

7 0
3 years ago
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