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Lostsunrise [7]
3 years ago
15

Find the concentration of H+ ions at a pH = 11 and

Chemistry
2 answers:
Black_prince [1.1K]3 years ago
6 0

Explanation:

the pH of the solution defined as negatuve logarithm of H^+ ion concentration.

pH=-\log[H^+]

1. Hydrogen ion concentration when pH of the solution is 11.

11=-\log[H^+]

[H^+]=1\times 10^{-11} mol/L..(1)

At pH = 11, the concentration of H^+ ions is 1\times 10^{-11} mol/L.

2. Hydrogen ion concentration when the pH of the solution is 6.

6=-\log[H^+]'

[H^+]'=1\times 10^{-6} mol/L..(2)

At pH = 6, the concentration of H^+ ions is 1\times 10^{-6} mol/L.

3. On dividing (1) by (2).

\frac{[H^+]}{[H^+]'}=\frac{1\times 10^{-11} mol/L}{1\times 10^{-6} mol/L}=1\times 10^{-5}

The ratio of hydrogen ions in solution of pH equal to 11 to the solution of pH equal to 6 is 1\times 10^{-5}.

4. Difference between the H^+ ions at both pH:

1\times 10^{-6} mol/L-1\times 10^{-11} mol/L=9.99\time 10^{-7} mol/L

This means that Hydrogen ions in a solution at pH = 7 has 9.99\time 10^{-7} mol/L ions fewer than in a solution at a pH = 6

Studentka2010 [4]3 years ago
4 0

Answer:

for table C

Explanation:

What is the concentration of H+ ions at a pH = 11?

1.  ⇒ 0.00000000001 mol/L  

What is the concentration of H+ ions at a pH = 6?

2.  ⇒ 0.000001 mol/L  

How many fewer H+ ions are there in a solution at a

pH = 11 than in a solution at a pH = 6?

3.  ⇒ 100,000

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