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3 years ago

4.4273 x 10 to the 5th divided by 5.3668 x 10 to the 3rd

Chemistry

1 answer:

Rasek [7]3 years ago

6 0

(4.4273 × 10¹⁰)/(5.3668 × 10³) = 0.824 94 × 10⁷ = 8.2494 × 10⁶

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How many electrons elements are present in period 2 ?

AVprozaik [17]

There are Eight elements

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3 years ago

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Rewrite the equation below using the correct conventions for stoichiometric coefficients. 2 BaCl2 + 2 H2SO4 → 2 BaSO4 + 4 HCl

vichka [17]

Answer:

$BaCl2+H2SO4 \rightarrow BaSO4+2HCl$

Explanation:

The given equation is:

$2 BaCl2+2H2SO4 \rightarrow2BaSO4+4HCl$

Based on the reaction stoichiometry:

2 moles of barium chloride (BaCl2) reacts with 2 moles of sulfuric acid (H2SO4) to form 2 moles of barium sulfate (BaSO4) and 4 moles of HCl

Although the reaction is balanced, the correct convention is to depict reactions in terms of the lowest molar ratio. Therefore the coefficients (2,2,4 and 4) can be divided by 2 to give:

$BaCl2+H2SO4 \rightarrow BaSO4+2HCl$

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3 years ago

Which type of electromagnetic wave has the most energy?

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Explanation:

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3 years ago

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Does anyone know what Hydrogen's oxidation state would be if it was acting as an anion non-metal?

Ilia_Sergeevich [38]

Answer:

yeah,The oxidation state of an atom does not represent the "real" charge on that atom, or any other actual atomic property.Hydrogen has OS = +1, but adopts −1 when bonded as a hydride to metals or metalloids. Oxygen in compounds has OS = −2. This set of postulates covers .

Explanation:

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3 years ago

A sample of a pure compound that weighs 60.3 g contains 20.7 g Sb (antimony) and 39.6 g F (fluorine). What is the percent compos

Volgvan

Answer:

The percent composition of fluorine is 65.67%

Explanation:

Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.

That is, the percentage composition is the percentage by mass of each of the elements present in a compound.

The calculation of the percentage composition of an element is made by:

$percent composition element A=\frac{total mass of element A}{mass of compound} *100$

In this case, the percent composition of fluorine is:

$percent composition of fluorine=\frac{39.6 g}{60.3 g} *100$

percent composition of fluorine= 65.67%

<u><em>The percent composition of fluorine is 65.67%</em></u>

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4 years ago