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marusya05 [52]
4 years ago
7

4.4273 x 10 to the 5th divided by 5.3668 x 10 to the 3rd

Chemistry
1 answer:
Rasek [7]4 years ago
6 0

(4.4273 × 10¹⁰)/(5.3668 × 10³) = 0.824 94 × 10⁷ = 8.2494 × 10⁶

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Robert Boyle made the biggest impact on science by __________.
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3 0
3 years ago
For the reaction 4FeCl2(aq) + 3O2(g) → 2Fe2O3(s) + 4Cl2(g), what volume of a 0.945 M solution of FeCl2 is required to react comp
Mnenie [13.5K]

Answer:

0.01M

Explanation:

Given paramters:

Volume of FeCl₂ = ?

Concentration = 0.945M

Number of molecules of O₂ = 4.32 x 10²¹molecules

Solution:

The balanced reaction equation is given below:

           4FeCl₂ + 3O₂ → 2Fe₂O₃ + 4Cl₂

Now, to solve the problem we use mole relationship between the compounds.

We work from the known to the unknown compounds. Here, the known is the oxygen gas because from the given parameters we can estimate the number of moles of the reacting gas.

  number of moles of O₂ = \frac{number of elementary of particles}{6.02 x 10^{23}}

number of moles of O₂ =  \frac{4.32 x 10^{21}}{6.02 x 10^{23}}

number of moles of O₂ = 0.007mole

now, from the reaction equation we find the number of moles of the FeCl₂:

   3 mole of O₂ reacted with 4 moles of FeCl₂

0.007mole of O₂ reacted with \frac{4 x 0.007}{3} = 0.0096mole O₂

Now to find the volume of FeCl₂ we use the expression below;

       volume of FeCl₂ = \frac{number of moles}{concentration}

                                   =  \frac{0.0096}{0.945}

                                    = 0.01L

7 0
3 years ago
A 519.93 gram sample of N2O is in a 7.05 L container. What is the pressure of the gas in atmospheres when the temperature is 125
Brut [27]

Answer:

17.27 atm

Explanation:

Use the ideal gas law or PV = nRT

We are solving for pressure here so lets isolate for P before we plug in values:

P = \frac{nRT}{V}

So first to get n or the number of moles we need to convert the grams of N2O to moles of N2O. We can do this by multiplying by the inverse of the molar mass like so:

\frac{519.93g(N2O)}{1} \frac{mol}{44.013g(N2O)}

Our grams of N2O would cancel and give us 11.813 mol of N2O

Now all thats left is to plug in and solve with the correct value for R which in this case for all of our units to cancel is 0.08206

P = \frac{(11.813)(0.08206)(125.63)}{7.05}

P = 17.27 atm

(I would double check the calculator work if it is for correctness just be sure)

4 0
3 years ago
Read 2 more answers
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