Answer:
a) Osmolarity measures the moles of solute per liter of solution.
Explanation:
Osmolarity is defined as the number of moles of solute that contribute to the osmotic pressure, per liter of solution, of solution. That is, the measurement of the solute concentration. The prefix "osmo-" indicates the possible variation of the osmotic pressure in the cells, which will occur when the solution is introduced into the body.
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A constant force F = 6i+8j-6k moves an object along a straight line from point (6, 0, -10) to point (-6, 7, 2).
Find the work done if the distance is measured in meters and the magnitude of the force is measured in newtons.
Answer:
the work done is -88 J
Explanation:
Given the data in the question;
we know that;
Work done = F × S
where constant force F = ( 6i + 8j - 6k )
S = ( -6i + 7j + 2k ) - ( 6i + 0j - 10k )
S = ( (-6i - 6i) + (7j - 0j) + ( 2k - ( -10k) ) )
S = ( -12I + 7j + 12k )
so
Work force = ( 6i + 8j - 6k ) × ( -12I + 7j + 12k )
Work force = ( 6 × -12 ) + ( 8 × 7 ) + ( -6 × 12 )
Work force = -72 + 56 - 72
Work force = -88 J
Therefore, the work done is -88 J
The total distance traveled by Aliaa using her skateboard for 20 revolution of the wheels is equal to 3770 millimeters.
<u>Given the following data:</u>
Diameter of skateboard = 60 mm.
Number of revolution = 20 revolutions.
Radius = diameter/2 = 60/2 = 30 mm.
<h3>What is distance?</h3>
Distance can be defined as the amount of ground covered (traveled) by a physical object over a specific period of time and speed, regardless of its direction, starting point or ending point.
For one revolution of the wheels, the distance traveled by Aliaa using her skateboard is given by:
Distance = 2πr
Distance = 2 × 3.142 × 30
Distance = 188.5 mm.
Therefore, the total distance traveled by Aliaa using her skateboard for 20 revolution of the wheels is given by:
Distance = 188.5 × 20
Distance = 3770 millimeters.
Read more on distance per revolutions here: brainly.com/question/10989073
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Explanation:
Distance = (intial speed)X(Time) + 1/2(acceleration)X(Time) [Third equation of motion]
As initial speed is zero, therefore;
Distance = 1/2(acceleration)X(Time)
= 1/2 (6 X 15)
= 1/2 (90)
= 45 meters
Hence, the object traveled 45 meters.
