Calculate the molar mass of Ca3P2 in grams per mole or search for a chemical formula or substance.
I believe it's a pure element
Answer:
Cupric ions
Explanation:
In the single displacement reaction shown, the cupric ions lost two electrons.
Cu²⁺ + 2e⁻ → Cu
The replacement of a metallic ion in solution by a metal atom higher in the activity series than than the metal in solution falls into this category of reactions.
Since Zn higher in the series, it displacements the cupric ions.
Answer:
NaZ + H2O <----> HZ + OH-
[OH-] = [HZ]
[NaZ] = 0.15 M
pH = 10.7, so the pOH = 14-10.7 = 3.3; [OH-] = 10^-3.3 = 5.01E-4
kb = [OH-][HZ]/[NaZ] = (5.01E-4)^2/0.15 = 1.67E-6
ka = kw/kb = 1E-14/1.67E-6 = 5.99E-9 = 6.0E-9
Answer:
<h2>8.13 mL</h2>
Explanation:
The required volume can be found by using the formula for Boyle's law
![V_2 = \frac{P_1V_1}{P_2} \\](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7BP_1V_1%7D%7BP_2%7D%20%20%5C%5C)
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
From the question we have
![V_2 = \frac{6.5 \times 1.25}{1} = 6.5 \times 1.25 \\ = 8.125](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7B6.5%20%5Ctimes%201.25%7D%7B1%7D%20%20%3D%206.5%20%5Ctimes%201.25%20%5C%5C%20%20%3D%208.125)
We have the final answer as
<h3>8.13 mL</h3>
Hope this helps you