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earnstyle [38]
3 years ago
7

A 25 kg ball is thrown into the air when thrown it's going 10 m/s calculate how high it travels

Physics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0
On Earth, the acceleration of gravity is 9.8 m/s² downward.
So any object with only gravity acting on it gains 9.8 m/s of
downward speed every second.

If the rock starts out moving upward at 10 m/s, then it will
continue upward for only  (10/9.8) = 1.02 second, before
it stops rising and starts falling.

Its average speed during that time is  (1/2) (10 + 0) = 5 m/s .

At an average speed of 5 m/s for 1.02 sec,
the rock rises

                   (5 m/s) x (1.02 sec)  =  5.102 meters .
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A truck travels 1430 m uphill along a road that makes a constant angle of 5.76◦ with the horizontal.
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Answer:

The horizontal component of displacement is d' = 1422.7 m

Explanation:

Given data,

The distance covered by the truck, d = 1430 m

The angle formed with the horizontal, Ф = 5.76°

The displacement is a vector quantity.

The horizontal component of displacement is given by,

                                 d' = d cos Ф

                                     = 1430 cos 5.76°

                                     = 1422.7 m

Hence, the horizontal component of displacement is d' = 1422.7 m

5 0
3 years ago
A ball is thrown up at a speed of 20 m/s.
ioda

Given:

(Initial velocity)u=20 m/s

At the maximum height the final velocity of the ball is 0.

Also since it is a free falling object the acceleration acting on the ball is due to gravity g.

Thus a=- 9.8 m/s^2

Now consider the equation

v^2-u^2= 2as

Where v is the final velocity which is measured in m/s

Where u is the initial velocity which is measured in m/s

a is the acceleration due to gravity measured in m/s^2

s is the displacement of the ball in this case it is the maximum height attained by the ball which is measured in m.

Substituting the given values in the above formula we get

0-(20x20)= 2 x- 9.8 x s

s= 400/19.6= 20.41m

Thus the maximum height attained is 20.41 m by the ball

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