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earnstyle [38]
3 years ago
7

A 25 kg ball is thrown into the air when thrown it's going 10 m/s calculate how high it travels

Physics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0
On Earth, the acceleration of gravity is 9.8 m/s² downward.
So any object with only gravity acting on it gains 9.8 m/s of
downward speed every second.

If the rock starts out moving upward at 10 m/s, then it will
continue upward for only  (10/9.8) = 1.02 second, before
it stops rising and starts falling.

Its average speed during that time is  (1/2) (10 + 0) = 5 m/s .

At an average speed of 5 m/s for 1.02 sec,
the rock rises

                   (5 m/s) x (1.02 sec)  =  5.102 meters .
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6 0
2 years ago
Specific heat is the amount of heat required to raise the temperature of a material by 1°C per what unit?
nydimaria [60]

The heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).


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3 0
3 years ago
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Do all objects have inertia <br><br> a) true<br> b) false
Natasha2012 [34]

Answer:

The answer is A. Which is true

4 0
3 years ago
A railroad car moves under a grain elevator at a constant speed of 3.20 m/s. Grain drops into the car at the rate of 240 kg/min.
dedylja [7]

Answer:

F = 768 N                  

Explanation:

It is given that,

Speed of the elevator, v = 3.2 m/s

Grain drops into the car at the rate of 240 kg/min, \dfrac{dm}{dt}=240\ kg/min = 4\ kg/s

We need to find the magnitude of force needed to keep the car moving constant speed. The relation between the momentum and the force is given by :

F=\dfrac{dp}{dt}

F=m\dfrac{dv}{dt}+v\dfrac{dm}{dt}

Since, the speed is constant,

F=m\dfrac{dv}{dt}

F=v\dfrac{dm}{dt}

F=3.2\times 240

F = 768 N

So, the magnitude of force need to keep the car is 768 N. Hence, this is the required solution.

5 0
3 years ago
While standing on a balcony a child drops a penny. The penny lands on the ground floor 1.5 s later. How fast was the penny trave
sveticcg [70]

Answer:

14.7 m/s.

Explanation:

From the question given above, the following data were obtained:

Time (t) = 1.5 s

Acceleration due to gravity (g) = 9.8 m/s².

Height = 11.025 m

Final velocity (v) = 0 m/s

Initial velocity (u) =?

We, can obtain the initial velocity of the penny as follow:

H = ½(v + u) t

11.025 = ½ (0 + u) × 1.5

11.025 = ½ × u × 1.5

11.025 = u × 0.75

Divide both side by 0.75

u = 11.025/0.75

u = 14.7 m/s

Therefore, the penny was travelling at 14.7 m/s before hitting the ground.

8 0
3 years ago
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