The given question is incomplete. The complete question is:
Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis. Determine the mass of glucose (C6H1206) produced
Answer: 60.0 g of glucose
Explanation:
To calculate the moles, we use the equation:
a) moles of
b) moles of
According to stoichiometry :
6 moles of
require = 6 moles of
Thus 2.0 moles of
require=
of
Thus
is the limiting reagent as it limits the formation of product.
As 6 moles of
give = 1 moles of glucose
Thus 2.0 moles of
give =
of glucose
Mass of glucose =
Thus 60.0 g of glucose will be produced from 88.0 g of carbon dioxide and 64.0 g of water
It is basic because of the fact that it has a strong base which is KOH and a weak acid HCN and the strong base causes it to remain more basic.
Answer:
Explanation:
First, let's review the ideal gas law, PV = nRT. In this equation, 'P' is the pressure in atmospheres, 'V' is the volume in liters, 'n' is the number of particles in moles, 'T' is the temperature in Kelvin and 'R' is the ideal gas constant (0.0821 liter atmospheres per moles Kelvin)