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3 years ago

The unit of force,newton is a derived unit.why?

Physics

2 answers:

denpristay [2]3 years ago

8 0

Answer:

The unit of force is a derived unit.

Why because it isn't part of the fundamental units which is MLT which stands for mass,length and time.....MLT are the units that brings out the derived units that's why it is called derived units because it is derived from fundamental units so Newton/force is not part of the fundamental unit and if we find the dimension of force you will see that it will be L^2T^-2.....which means it is derived from fundamental unit which makes it a derived unit....Thank you for the question

Alenkasestr [34]3 years ago

3 0

Answer: Newton, the unit of force, is defined based on Newton's Second Law (F=ma), as the force required to give a mass of one kilogram an acceleration of 1 meter/second2. Thus, it is derived from these other units.

Explanation:

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Answer:

$f_{e}$ = 1.9 cm

Explanation:

The magnification of a microscope is the product of the magnification of the eyepiece by the magnifier with the objective

M = M₀ $m_{e}$

Where M₀ is the magnification of the objective and $m_{e}$ is the magnification of the eyepiece.

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Substituting

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3 years ago

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4 years ago

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Explanation:

Let's count the forces acting on the bicylist:

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2) Normal reaction (N): this is the reaction force exerted by the road on the bicyclist. This force acts vertically upward, and it balances the weight, so its magnitude is equal to the weight of the bicyclist, and its direction is opposite

3) Applied force ( $F_A$ ): this is the force exerted by the bicylicist to push the bike forward. Its direction is forward

4) Air drag ( $R$ ): this is the force exerted by the air on the bicyclist and resisting the motion of the bike; its direction is opposite to the motion of the bike, so it is in the backward direction

So, we have 4 forces in total.

Here we can find the net force on the bicyclist by using Newton's second law of motion, which states that the net force acting on a body is equal to the product between the mass of the body and its acceleration:

$F_{net}=ma$