In short, and in general:
Advantages
<span>Credit Unions typically pay higher dividend rates on savingsCredit Unions typically offer lower rates on loansCredit Unions typically provide better service; since they are owned and governed by their membership, they tend to prioritize the needs of their members above all elseCredit Unions operate on a not-for-profit business model, so excess earnings are returned back to the membership in form of competitive rates and lower fees, and sometimes even special dividendsMany Credit Unions offer the same products and services found at banksCredit Unions often have added-value benefits, such as free financial education, discounted theme park tickets, and special member rates for services such as home alarm systems...even discounts at online retailers like Barnes & Noble.</span>Disadvantages
<span>Credit Unions, and in particular smaller local credit unions, struggle to match the level of convenience (ATMs and branches) that many banks provide their customers, although many CUs are part of shared networks which enhance the breadth of delivery channels available to their membersSome Credit Unions are limited in their product offeringsOne must qualify for membership <span>One must pay a membership fee to join. hope this helps!
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Hello! You can call me Emac or Eric.
I understand your problem, that question is pretty hard. But I found some information that I think you should read. This can get your problem done quickly.
Please hit that thank you button if that helped, I don’t want thank you’s I just want to know that this helped.
Please reply if this doesn’t help, I will try my best to gather more information or a answer.
Here is some good information that could help you out a lot!
Let’s begin by exploring some techniques astronomers use to study how galaxies are born and change over cosmic time. Suppose you wanted to understand how adult humans got to be the way they are. If you were very dedicated and patient, you could actually observe a sample of babies from birth, following them through childhood, adolescence, and into adulthood, and making basic measurements such as their heights, weights, and the proportional sizes of different parts of their bodies to understand how they change over time.
Unfortunately, we have no such possibility for understanding how galaxies grow and change over time: in a human lifetime—or even over the entire history of human civilization—individual galaxies change hardly at all. We need other tools than just patiently observing single galaxies in order to study and understand those long, slow changes.
We do, however, have one remarkable asset in studying galactic evolution. As we have seen, the universe itself is a kind of time machine that permits us to observe remote galaxies as they were long ago. For the closest galaxies, like the Andromeda galaxy, the time the light takes to reach us is on the order of a few hundred thousand to a few million years. Typically not much changes over times that short—individual stars in the galaxy may be born or die, but the overall structure and appearance of the galaxy will remain the same. But we have observed galaxies so far away that we are seeing them as they were when the light left them more than 10 billion years ago.
That is some information, I do have more if you need some! Thanks!
Have a great rest of your day/night! :)
Emacathy,
Brainly Team.
Maybe the picture helps. The blue block represents the cart with a mass of 3 kg. The person(black block) is pulling the cart to the right with a force F so that the acceleration a is 2 m/s². According to Newton's 2nd law: F = m*a.
Answer:
a) The x and y components of the momentum are 
and 
, respectively.
b) The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.
Explanation:
a) The vectorial equation of momentum is represented by the following expression:
(1)
Where:
- Vector momentum, measured in kilogram-meters per second.
- Mass of the particle, measured in kilograms.
- Vector velocity, measured in meters per second.
If we know that 
and ![\vec v = 2.98\,\hat{i}-3.98\,\hat{j}\,\,\,\left[\frac{m}{s} \right]](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%202.98%5C%2C%5Chat%7Bi%7D-3.98%5C%2C%5Chat%7Bj%7D%5C%2C%5C%2C%5C%2C%5Cleft%5B%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%5D)
, then the momentum is:
![\vec p = (2.93)\cdot (2.98\,\hat{i}-3.98\,\hat{j})\,\,\,\left[\frac{kg\cdot m}{s} \right]](https://tex.z-dn.net/?f=%5Cvec%20p%20%3D%20%282.93%29%5Ccdot%20%282.98%5C%2C%5Chat%7Bi%7D-3.98%5C%2C%5Chat%7Bj%7D%29%5C%2C%5C%2C%5C%2C%5Cleft%5B%5Cfrac%7Bkg%5Ccdot%20m%7D%7Bs%7D%20%5Cright%5D)
![\vec p = 8.731\,\hat{i}-11.661\,\hat{j}\,\,\,\left[\frac{kg\cdot m}{s} \right]](https://tex.z-dn.net/?f=%5Cvec%20p%20%3D%208.731%5C%2C%5Chat%7Bi%7D-11.661%5C%2C%5Chat%7Bj%7D%5C%2C%5C%2C%5C%2C%5Cleft%5B%5Cfrac%7Bkg%5Ccdot%20m%7D%7Bs%7D%20%5Cright%5D)
The x and y components of the momentum are and , respectively.
b) The magnitude and direction of momentum are represented by the following expressions:
(2)
(3)
Where:
- Magnitude of momentum, measured in kilogram-meters per second.
- Direction of momentum, measured in sexagesimal degrees.
If we know that 
and 
, then the magnitude and direction of momentum are, respectively:
The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.
