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Alisiya [41]
3 years ago
6

The unit of force,newton is a derived unit.why?​

Physics
2 answers:
denpristay [2]3 years ago
8 0

Answer:

The unit of force is a derived unit.

Why because it isn't part of the fundamental units which is MLT which stands for mass,length and time.....MLT are the units that brings out the derived units that's why it is called derived units because it is derived from fundamental units so Newton/force is not part of the fundamental unit and if we find the dimension of force you will see that it will be L^2T^-2.....which means it is derived from fundamental unit which makes it a derived unit....Thank you for the question

Alenkasestr [34]3 years ago
3 0

Answer: Newton, the unit of force, is defined based on Newton's Second Law (F=ma), as the force required to give a mass of one kilogram an acceleration of 1 meter/second2. Thus, it is derived from these other units.

Explanation:

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2 years ago
A positive charge +q1 is located to the left of a negative charge -q2. On a line passing through the two charges, there are two
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Answer:

please the answer below

Explanation:

(a) If we assume that our origin of coordinates is at the position of charge q1, we have that the potential in both points is

V_1=k\frac{q_1}{r-1.0}-k\frac{q_2}{1.0}=0\\\\V_2=k\frac{q_1}{r+5.2}-k\frac{q_2}{5.2}=0\\\\

k=8.89*10^9

For both cases we have

k\frac{q_1}{r-1.0}=k\frac{q_2}{1.0}\\\\q_1(1.0)=q_2(r-1.0)\\\\r=\frac{q_1+q_2}{q_2}\\\\k\frac{q_1}{r+5.2}=k\frac{q_2}{5.2}\\\\q_1(5.2)=q_2(r+5.2)\\\\r=\frac{5.2q_1-5.2q_2}{q_2}

(b) by replacing this values of r in the expression for V we obtain

k\frac{q_1}{\frac{5.2(q_1-q_2)}{q_2}+5.2}=k\frac{q_2}{5.2}\\\\\frac{q_1}{q_2}=\frac{(q_1-q_2)}{q_2}-1.0=\frac{q_1-q_2-q_2}{q_2}=\frac{q_1-2q_2}{q_2}

hope this helps!!

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3 years ago
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