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omeli [17]
3 years ago
15

In an internal combustion engine, platinum speeds up the oxidation of carbon monoxide to carbon dioxide. Platinum is needed for

the reaction, but is not used up in the reaction. How does platinum increase the rate of the reaction?
thinking either C or D

A. It raises the temperature.

B. It agitates the gases.

C. It acts as a catalyst.

D. It increases the pressure.
Chemistry
1 answer:
butalik [34]3 years ago
8 0
The answer is C, a catalyst. This is due to the fact that catalysts are substances that can be used to speed up a reaction by lowering the activation energy required. However, the catalyst itself is not actually used up during the reaction.
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4 0
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Read 2 more answers
Calculate the molarity of a 2.43 mol aqueous NaCl solution with a density of 2.00 g/mL.
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Explanation:

3 0
3 years ago
Look at the questions below and decide which is declarative.
Yuliya22 [10]
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3 0
3 years ago
If a particular ore contains 58.6 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp
rjkz [21]
Answer is: mass of the ore is 8.54kg.<span>

</span>ω(Ca₃(PO₄)₂ - calcium phosphate) = 58.6% ÷ 100% = 0.586.
m(P) = 1.00 kg · 1000 g/kg.
m(P) = 1000 g.
In one molecule of calcium phosphate there are two phosphorus atoms:
M(Ca₃(PO₄)₂) = 310.18 g/mol.
M(P) = 30.97 g/mol.
For one kilogram of phosphorus, we need:
M(Ca₃(PO₄)₂) : 2M(P) = m(Ca₃(PO₄)₂) : m(P).
310.18 g/mol : 61.94 g/mol = m(Ca₃(PO₄)₂) : 1000 g.
m(Ca₃(PO₄)₂) = 5007.75 g ÷ 1000 g/kg = 5.007 kg.
Mass of ore find from proportion:
m(Ca₃(PO₄)₂) : m(ore) = 56% : 100%.
m(ore) = 100% · 5.007 kg ÷ 58.6%.
m(ore) = 8.54kg.

5 0
3 years ago
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