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omeli [17]
3 years ago
15

In an internal combustion engine, platinum speeds up the oxidation of carbon monoxide to carbon dioxide. Platinum is needed for

the reaction, but is not used up in the reaction. How does platinum increase the rate of the reaction?
thinking either C or D

A. It raises the temperature.

B. It agitates the gases.

C. It acts as a catalyst.

D. It increases the pressure.
Chemistry
1 answer:
butalik [34]3 years ago
8 0
The answer is C, a catalyst. This is due to the fact that catalysts are substances that can be used to speed up a reaction by lowering the activation energy required. However, the catalyst itself is not actually used up during the reaction.
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A solution is prepared by dissolving ammonium sulfate in enough water to make of stock solution. A sample of this stock solution
Pani-rosa [81]

Answer: molarity of ammonium ions = 0.274mol/L

molarity of sulfate ions = 0.137mol/L

<em>Note: The complete question is given below</em>

A solution is prepared by dissolving 10.8 g ammonium sulfate in enough water to make 100.0 mL of stock solution. A 10.00-mL sample of this stock solution is added to 50.00 mL of water. Calculate the concentration of ammonium ions and sulfate ions in the final solution.

Explanation:

Molar concentration = no of moles/volume in liters

no of moles = mass/molar mass

mass of ammonium sulfate = 10.8g, molar mass of ammonium sulfate, (NH₄)₂SO₄ = (14+4)*2 + 32+ (16)*4 = 132g/mol

no of moles = 10.8g/132g/mol = 0.0820moles

<em>Molarity of stock solution = 0.0820mol/(100ml/1000ml* 1L) = 0.0820mol/0.1L Molarity of stock solution = 0.820mol/L</em>

Concentration of final solution is obtained from the dilution formula,

<em>C1V1 = C2V2</em>

C1 = 0.820M, V1 = 10mL, C2 = ?, V2 = 60mL

C2 = C1V1/V2

C2 = 0.820*10/60 = 0.137mol/L

molar concentration of ions = molarity of solution * no of ions

molarity of ammonium ions = 0.137mol/L * 2 = 0.274mol/L

molarity of sulfate ions = 0.137 mol/L * 1 = 0.137mol/L

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