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omeli [17]
3 years ago
15

In an internal combustion engine, platinum speeds up the oxidation of carbon monoxide to carbon dioxide. Platinum is needed for

the reaction, but is not used up in the reaction. How does platinum increase the rate of the reaction?
thinking either C or D

A. It raises the temperature.

B. It agitates the gases.

C. It acts as a catalyst.

D. It increases the pressure.
Chemistry
1 answer:
butalik [34]3 years ago
8 0
The answer is C, a catalyst. This is due to the fact that catalysts are substances that can be used to speed up a reaction by lowering the activation energy required. However, the catalyst itself is not actually used up during the reaction.
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Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it
Sauron [17]

Answer:

The concentration of COF₂ at equilibrium is 0.296 M.

Explanation:

To solve this equilibrium problem we use an ICE Table. In this table, we recognize 3 stages: Initial(I), Change(C) and Equilibrium(E). In each row we record the <em>concentrations</em> or <em>changes in concentration</em> in that stage. For this reaction:

   2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

I      2.00              0              0

C      -2x              +x            +x

E   2.00 - 2x         x              x

Then, we replace these equilibrium concentrations in the Kc expression, and solve for "x".

Kc=8.30=\frac{[CO_{2}] \times [CF_{4}] }{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } \\8.30=(\frac{x}{2.00-2x} )^{2} \\\sqrt{8.30} =\frac{x}{2.00-2x}\\5.76-5.76x=x\\x=0.852

The concentration of COF₂ at equilibrium is 2.00 -2x = 2.00 - 2 × 0.852 = 0.296 M

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