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Anuta_ua [19.1K]
3 years ago
5

On a hot summer day, air temperature is 30 °C and the actual vapor pressure is 30 mb: what is the approximate relative humidity

Physics
1 answer:
Lapatulllka [165]3 years ago
3 0

Answer:

chgfsgfsgsahfsgfggfsgasgsgfgfggdfdsseeerasfasfafvvdavadvdafdfgdb

Explanation:

bbfgfsgssdfeffsdfdffdgsgggfffrterrwrwftgwrtrtqvggsgfgdfhfghh

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a ray of light incident on a mirror, at an angle of 45°. Another mirror is placed at an angle of 45° to the first ones as shown.
Gwar [14]

Answer:

If the ray of light is deflected by 45 degrees by the first mirror its total deflection by mirror (I) is 90 deg. (incident = 45 and exit ray equals 45 deg)

The second mirror will cause a net deflection of 90 degrees and the total deflection will be 180 deg or in opposite  direction to the  incident ray.

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2 years ago
how does the number of chromosomes in a persons sex compare with the number of chromosome in the body cell
koban [17]

no it doesn't why because I think that it is not the same but different.

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3 years ago
The table and graph below show the distances traveled by two different objects. (3 points)
Aleks04 [339]

Answer:c

Explanation: the speed of object a changes but b travels at constant speed

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3 years ago
Two power lines run parallel for a distance of 222 m and are separated by a distance of 40.0 cm. if the current in each of the t
earnstyle [38]
1) Magnitude of the force:

The magnetic field generated by a current-carrying wire is
B= \frac{\mu_0I}{2 \pi r}
where
\mu_0 is the vacuum permeability
I is the current in the wire
r is the distance at which the field is calculated

Using I=135 A, the current flowing in each wire, we can calculate the magnetic field generated by each wire at distance 
r=40.0 cm=0.40 m, 
which is the distance at which the other wire is located:
B= \frac{\mu_0 I}{2 \pi r}= \frac{(4 \pi \cdot 10^{-7} N/A^2)(135 A) }{2 \pi (0.40 m)}=6.75 \cdot 10^{-5} T

Then we can calculate the magnitude of the force exerted on each wire by this magnetic field, which is given by:
F=ILB=(135 A)(222 m)(6.75 \cdot 10^{-5}T)=2.03 N

2) direction of the force: 
The two currents run in opposite direction: this means that the force between them is repulsive. This can be determined by using the right hand rule. Let's apply it to one of the two wires, assuming they are in the horizontal plane, and assuming that the current in the wire on the right is directed northwards:
- the magnetic field produced by the wire on the left at the location of the wire on the right is directed upward (the thumb of the right hand is directed as the current, due south, and the other fingers give the direction of the magnetic field, upward)

Now let's apply the right-hand rule to the wire on the right:
- index finger: current --> northward
- middle finger: magnetic field --> upward
- thumb: force --> due east --> so the force is repulsive

A similar procedure can be used on the wire on the left, finding that the force exerted on it is directed westwards, so the force between the two wires is repulsive.
6 0
3 years ago
Which of the following is an exercise myth?
Margaret [11]
The answere is No pain, no gain
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