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Finger [1]
3 years ago
7

Which of the following is a high impact activity? walking sprinting swimming sit-ups

Physics
2 answers:
Lena [83]3 years ago
8 0

sprinting is a high impact activity

Gnesinka [82]3 years ago
6 0

Answer: sprinting

Explanation:

The high impact activities are those activities which exerts direct force over the body. These activities includes the sports like football, running and gymnastics. These activities if done in excess can produce strain over the muscles and joints and may lead to injuries.

Sprinting is a running exercise which involves covering of a short distance in a limited period of time. It is likely to produce more strain over the body as compared to other activities. Therefore, it is an example of high impact activity.

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Describe how sound waves are produced by the drum and then heard.
Tamiku [17]

Answer:

The material stretched across the drum vibrates to produce the sound waves.

Explanation:

A drum is one of the oldest musical instrument made by man. It is made of a hollow body over which a material such as skin is stretched. When a drum is struck with a stick, the material vibrates up and down. This makes the air above the drum to contract and relax rhythmically resulting in soundwaves. The soundwaves travel through air to reach our ears where they are heard.

The quality of sound produced by  a drum is affected by its shape. A larger drum produces a lower pitched sound.

4 0
2 years ago
If the total charge on a rod of length 0.4 m is 2.6 nc, what is the magnitude of the electric field at a location 3 cm from the
Nana76 [90]
Let the rod be on the x-axes with endpoints -L/2 and L/2 and uniform charge density lambda (2.6nC/0.4m = 7.25 nC/m). 

The point then lies on the y-axes at d = 0.03 m. 

from symmetry, the field at that point will be ascending along the y-axes. 


A charge element at position x on the rod has distance sqrt(x^2 + d^2) to the point. 

Also, from the geometry, the component in the y-direction is d/sqrt(x^2+d^2) times the field strength. 


All in all, the infinitesimal field strength from the charge between x and x+dx is: 


dE = k lambda dx * 1/(x^2+d^2) * d/sqrt(x^2+d^2) 


Therefore, upon integration, 


E = k lambda d INTEGRAL{dx / (x^2 + d^2)^(3/2) } where x goes from -L/2 to L/2. 


This gives:


E = k lambda L / (d sqrt((L/2)^2 + d^2) ) 


But lambda L = Q, the total charge on the rod, so 


E = k Q / ( d * sqrt((L/2)^2 + d^2) )
3 0
2 years ago
In the case of the vacuum tube and movable stopper, what force moves the stopper?
sergejj [24]
I'm pretty sure it's the<span> impact of the air molecules on the outside of the stopper. They exert a net inward force, which is not resisted by anything on the other side.</span>
6 0
2 years ago
Read 2 more answers
15) On a cold day, you take in 4.2 L (i.e., 4.2 x 10-3 m3) of air into your lungs at a temperature of 0°C. If you hold your brea
Rudiy27

Answer:

4.8L ( i.e 4.8 x 10^-3 m3)

Explanation:

Step 1:

Data obtained from the question.

Initial volume (V1) = 4.2L

Initial temperature (T1) = 0°C

Final temperature (T2) = 37°C

Final volume (V2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature. This is illustrated below

K = °C + 273

T1 = 0°C = 0°C + 273 = 273K

T2 = 37°C = 37°C + 273 = 310K

Step 3:

Determination of the final volume.

Since the pressure is constant,

Charles' Law equation will be applied as shown below:

V1 /T1 = V2/T2

4.2/273 = V2 /310

Cross multiply to express in linear form

273 x V2 = 4.2 x 310

Divide both side by 273

V2 = (4.2 x 310)/273

V2 = 4.8L ( i.e 4.8 x 10^-3 m3)

Therefore, the volume of the air in the lungs at that point is 4.8L ( i.e 4.8 x 10^-3 m3)

3 0
3 years ago
Hii please help i’ll give brainliest!!
den301095 [7]

Answer:

C

Explanation:

6 0
2 years ago
Read 2 more answers
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