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maria [59]
3 years ago
13

It is responsible for the generation of earth’s magnetic field

Chemistry
2 answers:
morpeh [17]3 years ago
8 0

Answer: The magnetic field is generated by electric currents due to the motion of convection currents of a mixture of molten iron and nickel in the Earth's outer core: these convection currents are caused by heat escaping from the core, a natural process called a geodynamo.

Explanation:

PIT_PIT [208]3 years ago
3 0

Answer:

What is responsible for generating Earth's magnetic field?

Explanation:

On Earth, flowing of liquid metal in the outer core of the planet generates electric currents. The rotation of Earth on its axis causes these electric currents to form a magnetic field which extends around the planet.

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the recommended daily calcium I take for a woman over 50 years of age is 1200 mg. if one cup of milk has 306mg of Calcium how ma
Liono4ka [1.6K]
Intake 
divide the total amount of calcium 1200mg by the amount of calcium in one cup of milk 306mg and you will find that she needs about 4 cups of milk. To calculate the milliliters you need to know how many milliliters is one cup (1cup= 236.588 mL) and multiply by the number of cups that you calculate first.
6 0
3 years ago
What is the molarity of a 3.0-liter solution that contains 0.45 moles of solute?
jolli1 [7]
Molarity = moles / Volume in liters

M = 0.45 / 3.0

M = 0.15 mol/L 
5 0
2 years ago
Read 2 more answers
The density of benzene at 15 ∘C∘C is 0.8787 g/mL. Calculate the mass of 0.1700 LL of benzene at this temperature. Express your a
SVETLANKA909090 [29]

Answer:

Mass of benzene is: 149.3 g

Explanation:

Let's use density to calculate mass.

Density = Mass / Volume

Mass = Density . volume

Be careful, because density is in g/mL and the volume is in L. So let's convert the L to mL: 0.170 L . 1000 mL / 1L = 170 mL

0.8787 g/mL . 170 mL = Mass of benzene

Mass of benzene is: 149.3 g

5 0
3 years ago
Mole ratio of co2 carbonate to water
tino4ka555 [31]
Pls make ur question alittle clearer by may be saying the chemical compound or writing the required reaction

4 0
3 years ago
Calculate the entropy change for the surroundings of the reaction below at 350K: N2(g) + 3H2(g) -> 2NH3(g) Entropy data: NH3
krek1111 [17]

Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K

Explanation :

We have to calculate the entropy change of reaction (\Delta S^o).

\Delta S^o=S_{product}-S_{reactant}

\Delta S^o=[n_{NH_3}\times \Delta S^0_{(NH_3)}]-[n_{N_2}\times \Delta S^0_{(N_2)}+n_{H_2}\times \Delta S^0_{(H_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S^0{(NH_3)} = standard entropy of NH_3

\Delta S^0{(H_2)} = standard entropy of H_2

\Delta S^0{(N_2)} = standard entropy of N_2

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (192.5J/K.mole)]-[1mole\times (191.5J/K.mole)+3mole\times (130.6J/K.mole)]

\Delta S^o=-198.3J/K

Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K

4 0
2 years ago
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