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Alona [7]
2 years ago
9

7. What is the velocity of an object with a distance of 90m south and a time of 5s?

Physics
1 answer:
IrinaK [193]2 years ago
4 0

Answer:

Explanation:

v= s/t

V =90m/5s

V = 8m/s

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What is the momentum of a 72 kg baseball player who slides into home plate
Alina [70]

Answer:

B) 350 kg m/s

Explanation:

momentum or p is given by the equation p= mxv

We have the mass and velocity so we can use the equation directly

p= 72kg x 4.9 m/s

p= 352.8 kg m/s

4 0
2 years ago
Does the moon actually change shape as it revolves/rotates around the Earth? Explain your answer
rusak2 [61]

<u>Answer:</u>

<em>The moon doesn’t change shape on its own.</em>

<u>Explanation:</u>

Shapes of moon that we observe is based on the different perspectives of view from the earth and position of moon with respect to the sun. The changes arise due to the rotation of earth on its own axis as well as the revolution of moon on its orbit. The moon doesn’t have any light of its own.

It just reflects off the light from the sun. Due to tidal locking phenomenon one face of the moon permanently faces the sun. Because of the changes in position of moon with respect to the sun the moon is lighted up variably giving rise to various phases like new moon, full moon, crescent etc.

3 0
3 years ago
9As a student walks downhill at constant speed, his gravitational potential energy
Minchanka [31]

Answer:

jfsfjsjfsjfsjgsjfskra

Explanation:

sgnsfnNCzgnzncxmhshdgNdfjBFzktajfskgskgzngzngzgnzngzngzfNFzngzngznfzngzngzngzng

4)sfjskgdgxgkzhldlhdhkdkhdgkdkgzgksfnsksgkskfsufsursjfsjrsjfBFHDahdJFzbfzkgzndcxdnvxekvxlhecihckheclheclhexhiecohceoheclhecohecohecohceohceohecohceihcelhevlhecohcehlcegicgei.

4 0
3 years ago
A 1.89 kg object on a frictionless horizontal track is attached to the end of a horizontal spring whose force constant is 4.77 N
Maksim231197 [3]

Answer:

Magnitude F(t)=26.6 N

Direction: -x

Explanation:

Given data

Spring constant K=4.77 N/m

Mass m=1.89 kg

Displace A=5.56m

Time t=3.96s

To find

Magnitude of force F

Solution

The angular frequency is given as

w=\sqrt{\frac{K}{m} } \\w=\sqrt{\frac{4.77N/m}{1.89kg} }\\w=1.59rad/s

Force on object is

F(t)=-mAw^{2}Cos(wt)

Substitute given values

So

F(t)=-(1.89kg)(5.56m)(1.59rad/s)^{2}Cos(1.59*3.96)\\F(t)=-26.6N

So

Magnitude F(t)=26.6 N

Direction: -x

4 0
3 years ago
Please help! I will give brainliest!
irakobra [83]

Answer:

velocity because it says you are going 3 miles north and velocity is something  going a speed in a certian direction

Explanation:

3 0
3 years ago
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