Answer:
Option B is the correct answer.
Explanation:
Refer the figure we have centripetal force at bottom of circle

We have mass, m = 2 kg
Radius, r = 1.2 m
For circular motion to occur we have tension at top = 0
That is

Now let us find tension at bottom point

Option B is the correct answer.
#include<studio.h>
int main( )
{
int n;
int a,b,c,d,x,y;
int avarage;
printf("enter value of n:\n");
scanf("%d",&n);
printf("enter value of a:\n,b:\n,c:\n,d:\n,x:\n,y:\n);
scan f("%d\%d\n%d\n%d\n%d\n%d\n",&a,b,c,d,x,y);
sum=(a+b+c+d+x+y);
avarage=(sum/n);
print f("%d",avarage);
if
{
n=positive interger
}
else
{
printf ("n must be positive");
}
return 0;
}
Explanation:
<u>We</u><u> </u><u>call</u><u> </u><u>the</u><u> </u><u>magnitude</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>charge of </u><u>an</u><u> </u><u>electron</u><u> </u><u>as</u><u> </u><u>ELEMENTARY</u><u> </u><u>CHARGE</u><u>.</u>
The radio because u arent pushing as many watts out and it wont pass through as much
I think the answer is 3000 joules since work is force times distance.