Answer:
The Kf (Freezing Point Depression Constant) is been affect by freezing point among many other factor now using tap water for this experiment would mean that there would be salt present in the solution in that tap water is usually added fluoride which would react with the natural potassium present in the water to form a salt this salt would depress the freezing point of the water hence the value of Kf would be bigger that the actual value
Explanation:d
Answer:
460 g
Explanation:
Heat lost by the warm water = heat gained by the cold water
-mCΔT = mCΔT
-m (4.184 J/g/K) (37°C − 85°C) = (1000 g) (4.184 J/g/K) (37°C − 15°C)
-m (37°C − 85°C) = (1000 g) (37°C − 15°C)
-m (-48°C) = (1000 g) (22°C)
m = 458 g
Rounded to two significant figures, you need a mass of 460 g of water.
We have F = kx or ma = kx where m and k are constants. Therefore, if x is halved, a must be halved too.
Answer:
Time, t = 0.015 seconds.
Explanation:
Given the following data;
Mass, m = 0.2kg
Force, F = 200N
Initial velocity, u = 40m/s
Final velocity, v = 25m/s
To find the time;
Ft = m(v - u)
Time, t = m(v - u)/f
Substituting into the equation, we have;
Time, t = 0.2(25 - 40)/200
Time, t = 0.2(-15)/200
Time, t = 3/200
Time, t = 0.015 seconds.
Note: We ignored the negative sign because time can't be negative.
