Answer:
C. Neither
Explanation:
According to the periodic table, Hydrogen is in group 1 and period 1. Beryllium is in group 2, period 2.
We need to do some general algebra here.
We will find that you need 8.25 grams of CuNO₃ to make enough solution for the 22 labs.
<em>We know that:</em>
- Each lab group needs 25 ml of solution.
- it takes 15 g of CuNO₃ to make one L of that solution.
- There are 22 labs.
Because each lab needs 25 ml of solution, 22 labs will need that amount 22 times, so the <u>total amount of solution needed</u> is:
22*25ml = 550 ml
Now we know that we need 15 grams to make one liter of solution, and:
1 L = 1000ml
Then you need 15g to make 1000ml
and x (we want to find this amount) to make 550ml
Then we can write two equations (not actual equations, as these are different units) like:
x = 550ml
15g = 1000ml
Now we can take the quotient between these two equations:
x/15 g = (550ml/1000ml)
And now we can solve this for x:
x = (550ml/1000ml)*15g = 8.25g
So you need 8.25 grams of CuNO₃ to make enough solution for the 22 labs.
If you want to learn more, you can read:
brainly.com/question/8743486
Well, the sun is in space, right? It has to be able to transfer heat through space, or how would it get to us? Radiation helps transfer heat.
We are told that there are 1.55 x 10²³ molecules of Cl₂ and we need to calculate the mass of these molecules. We need to do several conversions. The easiest will be to convert the amount of molecules to the number of moles present. To do this, we need to use Avogadro's number which is 6.022 x 10²³ molecules/mole.
1.55 x 10²³ molecules / 6.022 x 10²³ molecules/mole = 0.257 moles Cl₂
Now that we have the moles of Cl₂ present, we can convert this value to a mass of Cl₂ by using the molecular mass of Cl₂. The molecular mass is 70.906 g/mol.
0.257 moles Cl₂ x 70.906 g/mol = 18.3 g Cl₂
Therefore, 1.55 x 10²³ molecules of Cl₂ will have a mass of 18.3 g.
Let's think, if you have a candle ( that is not blown out ) the physical properties are the candles mass and hence ( hence of the candle is the stiffness of the candle), weight, length, density, surface friction ( force resisting the relative motion of solid surface), and the energy content. You then, need to go to bed, so, therefore, you want to blow the candle out. Once you blow the candle out, the candle is evidently going to have at least a couple of different physical properties, than before it was blown out. The physical properties are a different color, the length of the candle, the texture, you could also apply the mass of the candleholder, and then, the mass of the candleholder and the candle, last but not least, the mass of just the candle. Once you observe the candle, you should be able to plug in those observations into the physical properties. As to, because you asked' what are the physical properties of a candle that has been blown out... We are going to assume that we did observe the candle, and the length of the candle in cm, after being blown out is 30cm. (12 inches; customary). Next, that the color of the candle is the same (let us say the original color is taffy pink). We can then say that the texture of the candle is waxy and the top and smooth as you get to the bottom ( the texture depends on how long the candle was burning, but we are saying that we lit the candle, and then immediately blew the flame out ) . We now have the mass of the candleholder, which will scientificity stay the same. Now, for the mass of the candleholder and the candle, that all depends of how long you let it burn ( remember, we are saying we lit the wick and then immediately blew the fame out ). So, the candle really didn't change is mass, so, therefore, wouldn't affect the mass of the candleholder including the candle. That also goes to the mass of the candle.
