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3 years ago

Is AG on the periodic table

1 answer:

Taya2010 [7]3 years ago

8 0

Ag on the periodic table is silver.
The atomic number for silver is 47, atomic symbol is Ag, and the atomic weight is 107.9.

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Two equal charges with magnitude Q and Q experience a force of 12.3442 when held at a distance r. What is the force between two

andre [41]

Answer:

197.5072.

Explanation:

According to the Coulomb's law, the magnitude of the electrostatic force of interaction between two charges $\rm q_1$ and $\rm q_2$ which are separated by the distance $\rm d$ is given by

$\rm F = \dfrac{kq_1q_2}{d^2}.$

<em>where,</em> k is the Coulomb's constant.

For the case, when,

$\rm q_1 = Q.$
$\rm q_2 = Q.$
$\rm d=r.$
$\rm F=12.3442.$

Then, using Coulomb's law,

$\rm 12.3442 = \dfrac{kQQ}{r^2}=\dfrac{kQ^2}{r^2}\ \ \ \ .......\ (1).$

For the case, when,

$\rm q_1 = 2Q.$
$\rm q_2 = 2Q.$
$\rm d=\dfrac r2.$

Then, using Coulomb's law, the new electric force between the charges is given by,

$\rm F' = \dfrac{k(2Q)(2Q)}{\left (\dfrac r2\right )^2}\\=\dfrac{k\ 4Q^2}{\dfrac{r^2}{4}}\\=4\times 4 \times \dfrac{kQ^2}{r^2}\\=16\ \dfrac{kQ^2}{r^2}\\=16\times 12.3442\ \ \ \ \ \ \ \ (Using\ (1))\\=197.5072.$

8 0

2 years ago

A 1200 kg car passes traffic light at a velocity of 10.2 m/s to the north and accelerates at a rate of 2.45 m/s^2. Calculate the

kumpel [21]

The car’s momentum after 4.21s is 24617.4 kgm/s

<h3>Newton's Second Law of Motion.</h3>

Newton's second law state that, the rate of change of momentum, is directly proportional to the applied force.

Given that a 1200 kg car passes traffic light at a velocity of 10.2 m/s to the north and accelerates at a rate of 2.45 m/s^2. To calculate the car’s momentum after 4.21 s, Let us first list all the parameters involved.

Velocity u = 10.2 m/s

Acceleration a = 2.45 m/s²

Mass m = 1200Kg

Time t = 4.21 s

From Newton's second law,

F = (mv - mu) / t

ma = (mv - mu) / t

Substitute all the parameters into the formula above.

1200 × 2.45 = ( mv - 1200 × 10.2 ) / 4.21

2940 = ( mv - 12240 ) / 4.21

Cross multiply

12377.4 = mv - 12240

Make mv the subject of the formula

mv = 12377.4 + 12240

mv = 24617.4 kgm/s

Therefore, the car’s momentum after 4.21s is 24617.4 kgm/s

Learn more about Momentum here: brainly.com/question/25121535

#SPJ1

3 0

1 year ago

A gold nucleus (with a radius of 6.5 fm in its rest system, containing 197 protons and neutrons of rest mass 939 MeV/c2 each) is

julia-pushkina [17]

Answer:

$1.9982154567\times 10^{-18}\ kgm/s$

762474.685899 MeV

3.1603639031 fm

Explanation:

v = 0.97 c

c = Speed of light = $3\times 10^8\ m/s$

Relativistic momentum is given by

$p=\dfrac{m_0v}{\sqrt{1-\dfrac{v^2}{c^2}}}\\\Rightarrow p=\dfrac{939\times 10^6\times 1.6\times 10^{-19}\times 0.97\times 3\times 10^8}{\sqrt{1-\dfrac{0.97^2c^2}{c^2}}}\\\Rightarrow p=\dfrac{(939\times 10^6\times 1.6\times 10^{-19})J/c^2\times 0.97c}{\sqrt{1-0.97^2}}\\\Rightarrow p=\dfrac{(939\times 10^6\times 1.6\times 10^{-19})\times 0.97}{c\sqrt{1-0.97^2}}\\\Rightarrow p=\dfrac{(939\times 10^6\times 1.6\times 10^{-19})\times 0.97}{3\times 10^8\times \sqrt{1-0.97^2}}\\\Rightarrow p=1.9982154567\times 10^{-18}\ kgm/s$

The momentum is $1.9982154567\times 10^{-18}\ kgm/s$

Energy in MeV

$E=\dfrac{m_0c^2}{\sqrt{1-\dfrac{v^2}{c^2}}}\\\Rightarrow E=\dfrac{939}{\sqrt{1-0.97^2}}\\\Rightarrow E=3862.52987766\ MeV$

Total energy is

$E'=3862.52987766+7.9=3870.42987766\ MeV$

The total energy is 3870.42987766 MeV

For all the nucleons

$E_t=197\times 3870.42987766=762474.685899\ MeV$

The energy is 762474.685899 MeV

Diameter = $2\times 6.5=13\ fm$

From length contraction

$D'=D\sqrt{1-\dfrac{v^2}{c^2}}\\\Rightarrow D'=13\sqrt{1-0.97^2}\\\Rightarrow D'=3.1603639031\ fm$

The diameter would be 3.1603639031 fm

3 0

3 years ago

The metabolic end-product(s) of the oxygen system is which of the following?

Dmitrij [34]

The metabolic end-product(s) of the oxygen system is Carbon dioxide and Water

<u>Explanation:</u>

Our body creates energy via combustion of carbohydrates , ammino acid and fats in presence of oxygen, this is called as aerobic metabolism.
Oxygen system in aerobic metabolism oxidizes carbohydrates and provide free oxygen atom .
These oxygen atom gets attached to carbon in the carbon dioxide molecule, which is excreted.
By products of such aerobic metabolism are carbon dioxide and water.

7 0

3 years ago

Why a rural area might be a safer place to experience an earthquake than a large city?

gladu [14]

Apparently, a large city consists of many infrastructures around. Once earthquake hits this area, there would be a very big chance that these buildings or bridges would collapse and this would result in more fatalities. In a rural area, you can only see a few of these and mostly, only plains or mountains are present.

6 0

3 years ago