Answer:
The length of the segment F'G' is 7.
Step-by-step explanation:
From Linear Algebra we define reflection across the y-axis as follows:
,
(Eq. 1)
In addition, we get this translation formula from the statement of the problem:
,
(Eq. 2)
Where:
- Original point, dimensionless.
- Transformed point, dimensionless.
If we know that
and
, then we proceed to make all needed operations:
Translation




Reflection


Lastly, we calculate the length of the segment F'G' by Pythagorean Theorem:
![F'G' = \sqrt{(5-5)^{2}+[(-1)-6]^{2}}](https://tex.z-dn.net/?f=F%27G%27%20%3D%20%5Csqrt%7B%285-5%29%5E%7B2%7D%2B%5B%28-1%29-6%5D%5E%7B2%7D%7D)

The length of the segment F'G' is 7.
Answer:
a. 10 + 2.50x
b. 60
c. 100
Step-by-step explanation:
a. 10 + 2.50x
b. 10 + 2.50(20)
= 10 + 50
= 60
c. 260 = 10 + 2.50x
250 = 2.50x
250/2.50 = x
x = 100
Answer = about 6,400 yards squared
Step-by-step explanation:
Answer:
58 yards^2
Step-by-step explanation:
You want to break this irregular shape into simple shapes. You can make a rectangle with the sides of 4 and 6 yards, whose are is 24 yards^2.
Then you can do the rectangle on the opposite side, whose sides are 4 and 6 yards, whose are is 24 yards^2 again.
Then the final rectangle has the sides of 5 and 2 yards, whose area is 10 yards^2.
If you add it all up, you will get 58 yards^2.