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lorasvet [3.4K]
3 years ago
5

Identify the reactants and the products of the preparation step to the urea cycle.

Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
7 0

According to sources, the most probable answer to this query is the enzymes and waste products that are collected by the nephron from the blood. Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
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Nitrogen monoxide, NO, is formed in automobile exhaust by the reaction of nitrogen and oxygen in the air: N2 (g) + O2 (g) ↔ NO (
Solnce55 [7]

Answer:

The equilibrium concentration of NO is 0.001335 M

Explanation:

Step 1: Data given

The equilibrium constant Kc is 0.0025 at 2127 °C

An equilibrium mixture contains 0.023M N2 and 0.031 M O2,

Step 2: The balanced equation

N2(g) + O2(g) ↔ 2NO(g)

Step 3:  Concentration at the equilibrium

[N2] = 0.023 M

[O2] = 0.031 M

Kc = 0.0025 = [NO]² / [N2][O2]

Kc = 0.0025 = [NO]² / (0.023)(0.031)

[NO] = 0.001335 M

The equilibrium concentration of NO is 0.001335 M

6 0
3 years ago
Why is potassium placed in the periodic table where it is?
Virty [35]
Potassium is placed where it is based on its properties and it's reactivity. It's also placed there based on it's atomic number. 
6 0
3 years ago
A 25.00 mL sample of the ammonia solution
musickatia [10]

Answer:

1.634 molL-1

Explanation:

The mol ration between NH3 and HCl is 1 : 1

Using Ca Va / Cb Vb = Na / Nb   where a = acid and b = base

Na = 1

Nb = 1

Ca = 0.208 molL-1

Cb = ?

Va = 19.64 mL

Vb = 25.00mL

Solving for Cb

Cb = Ca Va / Vb

Cb = 0.208 * 19.64 / 25.0

Cb = 0.1634 molL-1 (Concentration of diluted ammonia solution)

Using the dilution equation;

C1V1 = C2V2

Initial Concentration, C1 = ?

Initial Volume, V1 = 25.00 mL

Final Volume, V2 =  250 mL

Final Concentration, C2 = 0.1634 molL-1

Solving for C1;

C1 = C2 * V2 / V1

C1 = 0.1634 * 250 / 25.00

C1 = 1.634 molL-1

3 0
3 years ago
A intramuscular medication is given at 5.00mg/kg of body weight. What is the dose in grams for a 180-lb patient?
Alex17521 [72]
0.408 gram for 180-lb patient
7 0
3 years ago
Read 2 more answers
How many moles are in 2.04 x 10^8 atoms of calcium?
I am Lyosha [343]

Answer:

2.0 moles

Explanation:

I hope this helps you a little bit at least the answer is 2.0 but if you want to review more stuff check the photos

7 0
2 years ago
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