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3 years ago

Identify the reactants and the products of the preparation step to the urea cycle.

1 answer:

7 0

According to sources, the most probable answer to this query is the enzymes and waste products that are collected by the nephron from the blood. Thank you for your question. Please don't hesitate to ask in Brainly your queries.

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A solution is made by dissolving 0.0150 mol of HF in enough water to make 1.00 L of solution. At 26 °C, the osmotic pressure of

Alex777 [14]

Given:
M = 0.0150 mol/L HF solution
T = 26°C = 299.15 K
π = 0.449 atm

Required:
percent ionization

Solution:
First, we get the van't Hoff factor using this equation:
π = i MRT
0.449 atm = i (0.0150 mol/L) (0.08206 L atm / mol K) (299.15 K)
i = 1.219367

Next, calculate the concentration of the ions and the acid.
We let x = [H+] = [F-]
[HF] = 0.0150 - x

Adding all the concentration and equating to iM
x +x + 0.0150 - x = <span>1.219367 (0.0150)
x = 3.2905 x 10^-3

percent dissociation = (x/M) (100) = (3.2905 x 10-3/0.0150) (100) = 21.94%

Also,
percent dissociation = (i -1) (100) = (</span><span>1.219367 * 1) (100) = 21.94%</span>

7 0

3 years ago

Calculate the energy E of a sample of 3.50 mol of ideal oxygen gas (O2) molecules at a temperature of 310 K. Assume that the mol

love history [14]

Answer:

13.53 kJ

Explanation:

The energy of a gas can be calculated by the equation:

E = (3/2)*n*R*T

Where n is the number of moles, R is the gas constant (8.314 J/mol.K), and T is the temperature.

E = (3/2)*3.5*8.314*310

E = 13,531.035 J

E = 13.53 kJ

7 0

3 years ago

When 9.36 g sodium hydroxide is dissolved in enough water to make a total volume of 965 mL, what is the concentration of the res

SSSSS [86.1K]

Answer:

0.2425 M

Explanation:

Given mass = 9.36 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{9.36\ g}{39.997\ g/mol}$

$Moles\ of\ NaOH= 0.234\ mol$

Given that:- Volume = 965 mL = 0.965 L ( 1 mL = 0.001 L )

So,

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.234\ mol}{0.965\ L}=0.2425\ M$

5 0

3 years ago

Read 2 more answers

Which of the following is a physical property? A. Flammability B. Heat of combustion C. Solubility D.Toxicity

Rasek [7]

I think it would be solubility but I’m not sure

6 0

3 years ago

Read 2 more answers

2C3H7OH + 9O2 -> 6CO2 + 8H2O

MAVERICK [17]

Answer:

Up to $18\; \rm mol$ $\rm CO_2$ .

Explanation:

The equation for this reaction: $2\; \rm C_3 H_7 OH + 9\; O_2 \to 6\; CO_2 + 8\; H_2O$ is indeed balanced.

Notice that the coefficient of $\rm C_3 H_7 OH$ is $2$ while that of $\rm CO_2$ is $6$ .

Therefore, each unit of this reaction would consume $2$ units of $\rm C_3H_7OH$ while producing $6$ units of $\rm CO_2$ . In other words, this reaction would produce three times as much $\rm CO_2\!$ as it consumes $\rm C_3H_7OH\!$ .

If all that $6\; \rm mol$ of $\rm C_3H_7OH$ molecules are actually consumed through this reaction, three times as many $\rm CO_2$ molecules would be produced. That corresponds to $3 \times 6\; \rm mol = 18\; \rm mol$ of $\rm CO_2\!$ molecules.

6 0

3 years ago