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2 years ago

Calculate the wavelength (in nm) of a photon emitted when an electron

Chemistry

1 answer:

Fofino [41]2 years ago

4 0

<u>Answer</u>

657nm

Explanation

wavelength= 1/wavenumber

but wavenumber = RH×Z^2( (1/n1^2)-(1/n2^2))

where RH is the Rydberg constant = 1.0976×10^7

Z is the atomic number

n1 & n2 are orbitals

=(1.0976×10^7)×(1^2)×(1/4-1/9)

=1524444.444

but wavelength= 1/wavenumber

Therefore wavelength = 1/1524444.444

= 6.5597× 10^-7m

≈ 657nm

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How many neutrons are there in 9 molecules of P4 with mass number 31 and proton number 15?

aalyn [17]

A = mass number which is equal to the total number of protons + number of neutrons, Z= atomic number of any element which is also indicates Number of protons or number of electron in the given atom.

The formula to calculate neutron would be :

mass number - proton

31 - 15 = 16

Thus 16 neutrons are found in one atom of P

There are 4 atom in one molecule

Thus

4 atom /1 molecule * 9 molecule * 16 neutron / 1 atom

= 4*9*16= 576 neutrons

7 0

3 years ago

Read 2 more answers

Balance this equation and determine what the coefficients should be.

11Alexandr11 [23.1K]

Answer:

1, 2, 1, 1

Explanation:

3 0

3 years ago

Chemistry help please! I just need to make sure the answers correct.... Thank you!

Veronika [31]

1. At constant tempaerature and pressure, 3 tablets produce 600cm^3 of gas
Thus calculating for 1 tablet that produces 600 / 3 = 200 cm^3
So now two tablets produce 200 x 2 = 400 cm^3
2. We have the equation PV = nRT, n being the number of moles
Pressure P = 1,000 kPa
Volume V = 3 L
R = 8.31 L kPa/mol-K
Temperature T = 298 K
n = PV / RT = (1000 x 3) / (8.31 x 298) = 3000 / 2476.38 = 1.21 moles
Number of moles = 1.21 moles.

8 0

3 years ago

Consider the reaction between reactants s and o2: 2s(s)+3o2(g)→2so3(g)if a reaction vessel initially contains 7 mols and 9 mol o

nadya68 [22]

Answer: -

1 mol

Explanation: -

Number of moles of Sulphur S = 7

Number of moles of O2 = 9

The balanced chemical equation for the reaction is

2S (s)+3 O2 (g)→2SO3(g)

From the above reaction we can see that

3 mol of O2 react with 2 mol of S

9 mol of O2 will react with $\frac{2 mol S x 9 mol O2}{3 mol O2}$

= 6 mol of S

Unreacted S = 7 - = 1 mol.

If a reaction vessel initially contains 7 mol S and 9 mol O2

1 mole of s will be in the reaction vessel once the reactants have reacted as much as possible

6 0

3 years ago

Classify these substances? More than one answer may apply in each case.

dalvyx [7]

Answer:

N2 element, pure substance

O2 element, pure substance

N2O Compound, pure substance

Air (mostly N2 and O2 ) homogeneous mixture

Explanation:

N2, Nitrogen is known as the chemical element that is characterized by having atomic number 7 and that is symbolized by the letter N, in its molecular version, it is recognized as N2.

O2, Oxygen is the chemical element of atomic number 8, this molecular form is composed of two atoms of this element.

A chemical element is a type of matter, consisting of atoms of the same class.

N2O, Nitrous oxide is formed by the union of two molecules of nitrogen and one of oxygen, which is considered a chemical compound since it is a substance formed by the chemical combination of two different elements of the periodic table.

A pure substance is one that cannot change state or divide into other substances, except for a chemical reaction.

Air (mostly N2 and O2 ), it is a homogeneous mixture of gases that constitutes the earth's atmosphere. A homogeneous mixture is a type of mixture in which its components are not distinguished and in which the composition is uniform and each part of the solution has the same properties.

3 0

3 years ago