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agasfer [191]
2 years ago
13

Calculate the wavelength (in nm) of a photon emitted when an electron

Chemistry
1 answer:
Fofino [41]2 years ago
4 0

<u>Answer</u>

657nm

Explanation

wavelength= 1/wavenumber

but wavenumber = RH×Z^2( (1/n1^2)-(1/n2^2))

where RH is the Rydberg constant = 1.0976×10^7

Z is the atomic number

n1 & n2 are orbitals

=(1.0976×10^7)×(1^2)×(1/4-1/9)

=1524444.444

but wavelength= 1/wavenumber

Therefore wavelength = 1/1524444.444

= 6.5597× 10^-7m

≈ 657nm

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What is the best way to combine these sentences? The frogs front feet have 4 toes. Its back feet have 5 toes
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8 0
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How many moles of silver can be produced from silver nitrate from 1 mole of zinc?
jasenka [17]

Answer:

Answer: 6.5 moles of silver metal is formed in the given chemical reaction. The moles of excess reagent left are 0.55 moles.

Explanation:

To calculate the moles of silver formed and the moles of excess reagent left after the reaction, we need to balance the equation first and need to find the limiting and excess reagent.

The balanced chemical equation is:

Zn + 2AgNO3 ---> Zn (NO3)2 +2Ag

By Stoichiometry:

2 moles of Silver nitrate reacts with 1 mole of Zinc metal

So, 6.5 moles of silver nitrate will react with = 1/2 x 6.5 = 3.25 moles of zinc metal

The required amount of zinc metal is less than the given amount of zinc metal,  hence, it is considered as an excess reagent.

Therefore, silver nitrate is the limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 2 moles of silver metal

So, 6.5 moles of silver nitrate will produce = 2/2 x 6.5 = 6.5moles of silver metal.

Number of moles of excess reagent left after the completion of reaction = (3.8 - 3.25)moles = 0.55 moles

Hence, 6.5 moles of silver metal is formed in the given chemical reaction. The moles of excess reagent left are 0.55 moles.

4 0
1 year ago
You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute b
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Answer:

             0.045 L  or 45 mL

Explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

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Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L

8 0
2 years ago
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