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agasfer [191]
2 years ago
13

Calculate the wavelength (in nm) of a photon emitted when an electron

Chemistry
1 answer:
Fofino [41]2 years ago
4 0

<u>Answer</u>

657nm

Explanation

wavelength= 1/wavenumber

but wavenumber = RH×Z^2( (1/n1^2)-(1/n2^2))

where RH is the Rydberg constant = 1.0976×10^7

Z is the atomic number

n1 & n2 are orbitals

=(1.0976×10^7)×(1^2)×(1/4-1/9)

=1524444.444

but wavelength= 1/wavenumber

Therefore wavelength = 1/1524444.444

= 6.5597× 10^-7m

≈ 657nm

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Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:
antoniya [11.8K]

The electron group arrangement of PH₃ is tetrahedral. The molecular shape is a Trigonal pyramid, and the bond angle is 93°.

<h3>What is the bond angle?</h3>

The angle between the atoms in a compound is known as the bond angle. The degree of the binding angle is specified. There is also the bond length. It is the separation between the two atoms' nuclei.

The bond angle between the atoms of phosphine is 93°. It has one lone pair. The central atom is covered with 4 atoms.

Thus, the electron-group arrangement of phosphine is tetrahedral. The molecular geometry or shape is a trigonal pyramid. The bond angle is 93°.

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2 years ago
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So here, oxidation state of nitrogen is changing from 0 to -3. Whereas oxidation state of hydrogen is changing from 0 to +3.

Reaction between ammonia and nitric acid will be as follows.

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