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pishuonlain [190]
4 years ago
13

How to overcome fearing accomplishments

Physics
2 answers:
Rashid [163]4 years ago
8 0
If you need anyone to talk to im always here even though you dont know me i struggle with a lot of things and this one of them so im always here :)
stepan [7]4 years ago
6 0
The best thing to do is start out small. Do something that is in your comfort zone and get bigger each time. Before you know it, you will have gotten over your fear and it'll feel great :)
You might be interested in
If a transverse wave osculates 7 times every second and the speed of the wave is 27 m/s what is the wavelength of the wave
Inessa05 [86]

Explanation:

formula is ˠ=vf

f=1/T

1/7

f=0.14

wavelength=27Ⅹ0.14

=3.78m

OR

7Ⅹ27

=189m

5 0
2 years ago
if a body of mass 2kg moving with Velocity of 15m/s collides with a stationary body of same mass then after elastic collision 2n
pochemuha

Answer:

v = 15 [m/s]

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is equal to the product of mass by Velocity.

P=m*v

where:

P = linear momentum [kg*m/s]

m = mass = 2 [kg]

v = velocity = 15 [m/s]

P=2*15\\P=30 [kg*m/s]

Since we know that momentum is conserved, that is, all momentum is transferred to the second body, we can determine the velocity of the second body, since the mass is equal to that of the first body.

30=2*v\\v = 30/2\\v = 15 [m/s]

5 0
3 years ago
At some airports there are speed ramps to help passengers get from one place to another. A speed ramp is a moving conveyor belt
Amanda [17]

Answer:

The time taken is t_s = 31.16 s

Explanation:

From the question we are told that

   The length of the speed ramp is L = 104m

     The speed of the speed ramp is v_r  = 2.1 m/s

      The time taken to cover the distance is t = 84 s

     

The walking speed( when not on the speed ramp)  required to  cover the 104m is mathematically represented as

                     v_w = \frac{L}{t}

Substituting values

                      v_w = \frac{104}{84}

                            = 1.238 m/s

The speed required to cover the 104m distance when on a speed speed ramp  is mathematically represented as

     v = The\ walking\ speed  +  speed \ of \ the \ speed \ ramp

 substituting values

               v = 2.1 + 1.238

               v = 3.338 m/s

Now the time taken to travel the 104m distance when walking on the speed ramp is mathematically evaluated as

                t_s = \frac{L}{v}

                     = \frac{104}{3.338}

                     t_s = 31.16 s

             

4 0
3 years ago
Read 2 more answers
A 6 kg bowling ball is accelerated at a rate of 2.3 m/s² down the lane. How much force was necessary to produce this acceleratio
Maurinko [17]
The answer is D hoped this helped
4 0
3 years ago
On your first trip to Planet X you happen to take along a 180 g mass, a 40-cm-long spring, a meter stick, and a stopwatch. You'r
lys-0071 [83]

Answer:

g_x = 3.0 m / s^2

Explanation:

Given:

- Change in length of spring [email protected] = 22.6 cm

- Time taken for 11 oscillations t = 19.0 s

Find:

- The value of gravitational free fall g_x at plant X:

Solution:

- We will assume a simple harmonic motion of the mass for which Time is:

                                 T  = 2*pi*sqrt(k / m )    ...... 1

- Sum of forces in vertical direction @equilibrium is zero:

                                 F_net = k*x - m*g_x = 0

                                 (k / m) = (g_x / x)    .... 2

- substitute Eq 2 into Eq 1:

                                  2*pi / T = sqrt ( g_x / x )

                                   g_x = (2*pi / T )^2 * x

- Evaluate g_x:

                                  g_x = (2*pi / (19 / 11) )^2 * 0.226

                                  g_x = 3.0 m / s^2

                                 

                       

3 0
4 years ago
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