Answer:
v = 15 [m/s]
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is equal to the product of mass by Velocity.

where:
P = linear momentum [kg*m/s]
m = mass = 2 [kg]
v = velocity = 15 [m/s]
![P=2*15\\P=30 [kg*m/s]](https://tex.z-dn.net/?f=P%3D2%2A15%5C%5CP%3D30%20%5Bkg%2Am%2Fs%5D)
Since we know that momentum is conserved, that is, all momentum is transferred to the second body, we can determine the velocity of the second body, since the mass is equal to that of the first body.
![30=2*v\\v = 30/2\\v = 15 [m/s]](https://tex.z-dn.net/?f=30%3D2%2Av%5C%5Cv%20%3D%2030%2F2%5C%5Cv%20%3D%2015%20%5Bm%2Fs%5D)
Answer:
The time taken is 
Explanation:
From the question we are told that
The length of the speed ramp is 
The speed of the speed ramp is 
The time taken to cover the distance is 
The walking speed( when not on the speed ramp) required to cover the 104m is mathematically represented as

Substituting values


The speed required to cover the 104m distance when on a speed speed ramp is mathematically represented as

substituting values


Now the time taken to travel the 104m distance when walking on the speed ramp is mathematically evaluated as



Answer:
g_x = 3.0 m / s^2
Explanation:
Given:
- Change in length of spring [email protected] = 22.6 cm
- Time taken for 11 oscillations t = 19.0 s
Find:
- The value of gravitational free fall g_x at plant X:
Solution:
- We will assume a simple harmonic motion of the mass for which Time is:
T = 2*pi*sqrt(k / m ) ...... 1
- Sum of forces in vertical direction @equilibrium is zero:
F_net = k*x - m*g_x = 0
(k / m) = (g_x / x) .... 2
- substitute Eq 2 into Eq 1:
2*pi / T = sqrt ( g_x / x )
g_x = (2*pi / T )^2 * x
- Evaluate g_x:
g_x = (2*pi / (19 / 11) )^2 * 0.226
g_x = 3.0 m / s^2