I added individual steps for clarity. Note that g must be positive if the solution is to be real.

Let me know if you have any questions.
Explanation:
The 11Ω, 22Ω, and 33Ω resistors are in parallel. That combination is in series with the 4Ω and 10Ω resistors.
The net resistance is:
R = 4Ω + 10Ω + 1/(1/11Ω + 1/22Ω + 1/33Ω)
R = 20Ω
Using Ohm's law, we can find the current going through the 4Ω and 10Ω resistors:
V = IR
120 V = I (20Ω)
I = 6 A
So the voltage drops are:
V = (4Ω) (6A) = 24 V
V = (10Ω) (6A) = 60 V
That means the voltage drop across the 11Ω, 22Ω, and 33Ω resistors is:
V = 120 V − 24 V − 60 V
V = 36 V
So the currents are:
I = 36 V / 11 Ω = 3.27 A
I = 36 V / 22 Ω = 1.64 A
I = 36 V / 33 Ω = 1.09 A
If we wanted to, we could also show this using Kirchhoff's laws.
Forces occur in pairs and can be either balanced or unbalanced. Balanced forces do not cause a change in motion. Unbalanced Forces do cause a change in motion.
Answer:
(a) angle record will be 46°
Explanation:
We have given speed = 33 rpm
Time t = 0.23 sec
We know that 1 revolution = 360°
And 1 minute = 60 sec
So 33 revolution/minute 
So angle record by vinyl
, which is nearly equal to 46
So angle record by vinyl is 46°
So option (a) will be the correct answer
Answer:
d. 6/5 M.
Explanation:
let the angular velocity = 
the radius of sphere (r) = 
moment of inertia of solid sphere
= 
rotational K.E of solid sphere= 
= 
we represent the mass of hallow sphere= 
moment of inertia of solid sphere
= 
rotational K.E of hollow sphere= 
= 
NOW,the kinetic energy of solid sphere= 1/2 kinetic energy of hallow sphere
=![1/2 [2/5 M(D/2)^2 ]\omega^2= 1/2 (1/2 (2/3 M_{hs}(D/2)^2 )\omega^2 }](https://tex.z-dn.net/?f=1%2F2%20%5B2%2F5%20M%28D%2F2%29%5E2%20%5D%5Comega%5E2%3D%201%2F2%20%281%2F2%20%282%2F3%20M_%7Bhs%7D%28D%2F2%29%5E2%20%29%5Comega%5E2%20%7D)
2/5M= 1/3
= 3(2/5M)
= 6/5 M